626 reputation
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location Washington, DC
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visits member for 3 years
seen Nov 14 at 6:22
My name is Boda Cydo. I am from Africa but now live in Washington DC.

Nov
4
comment How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
It helped. Thanks a lot!
Nov
4
accepted How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
@Unnamed Thanks everyone!
Nov
4
accepted How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
But I can still have two one-sided limits, right? There is left sided limit, right sided limit and the one when both come together, correct?
Nov
4
comment How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
OOoppppsssssss.......
Nov
4
comment How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
Thanks @digital brain. Yes, I was talking about Lospitahl Rule. What about one-sided limits though?
Nov
4
comment How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
@Lolman 1/x is infinity
Nov
4
comment How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
@AndréNicolas I think the same thing happens? Is there any difference if I approach from left or right? I end up at 3 in both cases?
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
Because limits from both sides have to be equal for limit to exist, yes?
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
Oh wait... You say it doesn't exist...? Why?
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
I solved it, the limit is $\sqrt(2)$ if x goes to $0$ from positive, and it's $-\sqrt(2)$ if x goes to $0$ from negative. :)
Nov
4
comment How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
Thanks, let me try :))) I'll get back to you soon
Nov
4
asked How to solve limit of $\frac{x^x}{(x-3)^3}$ when x goes to 3?
Nov
4
asked How to solve a $\lim_{x\to 0}\frac{\sqrt{1-\cos2x}}{x}$?
Oct
6
awarded  Benefactor
Oct
5
comment How to solve this limit $\lim_{n\to\infty} ((\frac{1}{\sqrt{n^2+1}}) + \cdots + (\frac{1}{\sqrt{n^2+n}}))$
Thankssssssss it helped so much. :))) It will take some time before I can apply it somewhere. This is much higher level math... :))
Oct
5
comment How to solve this limit $\lim_{n\to\infty} ((\frac{1}{\sqrt{n^2+1}}) + \cdots + (\frac{1}{\sqrt{n^2+n}}))$
@ByronSchmuland Wow... You're right. n is fixed for all terms, rather changing from 1 to n for every term...
Oct
5
comment How to solve this limit $\lim_{n\to\infty} ((\frac{1}{\sqrt{n^2+1}}) + \cdots + (\frac{1}{\sqrt{n^2+n}}))$
Thanks, the first part is now clear. The second part ... it's not quite clear how you went from $$\sqrt{n^2+i}$$ in the denominator to $$\sqrt{1+xdx}$$ ... and it's also not clear how you went from $$\frac{dx}{\sqrt{1+xdx}}$$ to just $$dx$$. Did I make myself clearer?
Oct
5
comment How to solve this limit $\lim_{n\to\infty} ((\frac{1}{\sqrt{n^2+1}}) + \cdots + (\frac{1}{\sqrt{n^2+n}}))$
Thanks, but this is a bit way over my understanding :) For example, how did you go in the last equation to integral from 0 to 1, rather than from 1 to infinity? Also... how did you end up with $$sqrt(1 + x*dx)$$ ... Also how did nominator and denominator cancel to just have $dx$...