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visits member for 2 years, 11 months
seen Apr 27 at 15:34

Apr
28
awarded  Scholar
Apr
27
accepted Seeking proper terminology
Apr
27
asked Seeking proper terminology
Oct
30
comment Why are Mersenne primes easier to find?
Any prime divisor of 2^p-1 must be of the form 2kp+1. Thus "in particular no prime less than 2p can be a divisor.".
Mar
31
awarded  Supporter
Nov
29
awarded  Teacher
Nov
29
answered computing primes
Nov
27
comment Integer exponentiation algorithm for the special case $3^n$
@HenningMakholm: That's correct. The referenced Knuth's algorithm exploits the binary representation of the exponent, so let me clarify - I need the binary result to work with it in an ordinary binary computer.
Nov
27
comment Integer exponentiation algorithm for the special case $3^n$
@Simone: I believe so even though I don't have the referenced print physically available.
Nov
27
awarded  Student
Nov
27
awarded  Analytical
Nov
27
asked Integer exponentiation algorithm for the special case $3^n$