4,928 reputation
1626
bio website
location
age
visits member for 2 years, 5 months
seen yesterday

Undergraduate math major


Apr
2
accepted Why $\frac{|1-z|}{1-|z|}\le K$ corresponds to the region defined by the Stolz angle?
Feb
14
asked Reference on $\mathcal{L}^p(I;X)$
Feb
14
awarded  Popular Question
Feb
4
accepted Euler-Lagrange: Motivation for Definition of Weak Solutions
Jan
31
answered Euler-Lagrange: Motivation for Definition of Weak Solutions
Jan
27
awarded  Nice Question
Jan
26
asked Euler-Lagrange: Motivation for Definition of Weak Solutions
Jan
22
asked Why $\frac{|1-z|}{1-|z|}\le K$ corresponds to the region defined by the Stolz angle?
Jan
5
comment Why most of the continuous transforms are based on integral operator?
They are the origin.
Jan
2
accepted Motivation for abstract harmonic analysis
Dec
28
comment Differences between $L^p$ and $\ell^p$ spaces
Might worth mentioning: the major difference between $\ell^p$ and $\mathcal{L}^p$ is that functions in $\mathcal{L}^p$ can have local fluctuations, while functions in $\ell^p$ cannot. This difference comes from the fact that $\mathbb{Z}$ is an atomic measure space while in general a measure space, on which we build $\mathcal{L}^p$, can be much more complicated.
Dec
25
comment Smallest non-commutative ring with unity
Rumor has it that $\{0\}$ is a perfectly-defined commutative ring with unity XD
Dec
25
comment finite group whose only automorphism is identity map
Yes, these are cute little facts XD
Dec
25
answered finite group whose only automorphism is identity map
Dec
25
comment Is the Hilbert parallelotope compact?
It is compact, but the two topologies are different.
Dec
23
answered 2 Tricks to prove Every group with an identity and x*x = identity is Abelian - Fraleigh p. 48 4.32
Dec
23
accepted What's behind the function $g(x)=\operatorname{inf}\{f(p)+d(x,p):p\in X\}$?
Dec
23
comment What's behind the function $g(x)=\operatorname{inf}\{f(p)+d(x,p):p\in X\}$?
Thanks! Very clear explanation.
Dec
23
asked What's behind the function $g(x)=\operatorname{inf}\{f(p)+d(x,p):p\in X\}$?
Dec
15
answered Why is the following identity true? $E[Y] = \int_{0}^{\infty}P\left \{ Y>x \right \}{d}x$