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May
14
accepted Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
May
14
revised Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
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May
14
awarded  Commentator
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
Is my question clear, do you see what I'm asking?
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
@Gigili I think I learned it now by looking at your edit. Thanks!
May
14
revised Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
deleted 4 characters in body
May
14
reviewed Approve suggested edit on Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
@Gigili Sorry, but I don't know LaTeX...
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
10C7 can be written as (10x9x8x7x6x5x4)/(7x6x5x4x3x2x1) to find how many ways 7 "correct" can happen out of 10 trials. But, why? Why can you write it like that? It's a poor example, but 5^2x5^3=5^3+2=5^5 because 5x5 x 5x5x5 = 5^5... X^n x X^m = X^n+m. It's a rule that works, but why does this rule about 10C7 work?
May
14
asked Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
Dec
12
awarded  Scholar
Dec
12
comment Solving Linear Equation in One Unknown
I know, they are! I didn't realize that it was one term, so it got -3 instead of +3. Thanks everyone!
Dec
12
accepted Solving Linear Equation in One Unknown
Dec
12
comment Solving Linear Equation in One Unknown
Thanks, but 12x-3x, then you wrote -3, why isn't it +3? it says x+1 and not -1. Hopefully this is where I left of. Edit: Is x+1 one term? So it's like -(x+1) = -x-1 to remove the brackets?
Dec
12
awarded  Editor
Dec
12
comment Solving Linear Equation in One Unknown
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Dec
12
revised Solving Linear Equation in One Unknown
added 174 characters in body
Dec
12
asked Solving Linear Equation in One Unknown
Nov
20
comment Recipe for solving equations
In UK English it's called lower secondary school. I mean the equations you learn there.
Nov
20
comment Recipe for solving equations
I think I have formulated myself poorly. I was asking if anyone knew about a recipe for solving all middle school algebra equations.