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seen Sep 16 at 9:39

May
14
awarded  Supporter
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
Normally, I wouldn't spam with a comment that is of no use. But this time I have to! This is a GREAT answer! This deserves +2!
May
14
accepted Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
May
14
revised Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
added 36 characters in body
May
14
awarded  Commentator
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
Is my question clear, do you see what I'm asking?
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
@Gigili I think I learned it now by looking at your edit. Thanks!
May
14
revised Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
deleted 4 characters in body
May
14
reviewed Approve suggested edit on Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
@Gigili Sorry, but I don't know LaTeX...
May
14
comment Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
10C7 can be written as (10x9x8x7x6x5x4)/(7x6x5x4x3x2x1) to find how many ways 7 "correct" can happen out of 10 trials. But, why? Why can you write it like that? It's a poor example, but 5^2x5^3=5^3+2=5^5 because 5x5 x 5x5x5 = 5^5... X^n x X^m = X^n+m. It's a rule that works, but why does this rule about 10C7 work?
May
14
asked Why does $\binom{10}{7} = \frac{10!}{(10-7)!7!}$
Dec
12
awarded  Scholar
Dec
12
comment Solving Linear Equation in One Unknown
I know, they are! I didn't realize that it was one term, so it got -3 instead of +3. Thanks everyone!
Dec
12
accepted Solving Linear Equation in One Unknown
Dec
12
comment Solving Linear Equation in One Unknown
Thanks, but 12x-3x, then you wrote -3, why isn't it +3? it says x+1 and not -1. Hopefully this is where I left of. Edit: Is x+1 one term? So it's like -(x+1) = -x-1 to remove the brackets?
Dec
12
awarded  Editor
Dec
12
comment Solving Linear Equation in One Unknown
Added a picture
Dec
12
revised Solving Linear Equation in One Unknown
added 174 characters in body
Dec
12
asked Solving Linear Equation in One Unknown