Danikar
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 Feb4 awarded Popular Question Nov16 awarded Popular Question Nov15 awarded Yearling Nov13 awarded Promoter Nov11 asked Algorithm to compute fastest method of collecting $k$ re-spawning items which spawn at $n$ specified points Oct8 revised $\lfloor x\rfloor + \lfloor y\rfloor \leq \lfloor x+y\rfloor$ for every pair of numbers of $x$ and $y$ added 4 characters in body Oct8 answered $\lfloor x\rfloor + \lfloor y\rfloor \leq \lfloor x+y\rfloor$ for every pair of numbers of $x$ and $y$ Sep5 awarded Nice Question Aug13 awarded Notable Question Aug7 comment Countability of Sets @TomCollinge Look at the second paragraph of that article. Some books don't count finite sets as countable. Jul9 answered Calc 2: convergent of divergent sequences Jul2 awarded Curious Jun21 awarded Popular Question Jun4 answered Sum of $\mathbf{x}\mathbf{x}'\mathbf{x}\mathbf{x}'$ when $\mathbf{x}$ is a binary vector of length $n$ May4 comment Let $G$ be a connected graph. If $G$ has no cut vertices, then G has no bridges. @CharlesNosbig yeah, I would say that is the correct answer. Although if this is homework, it might be cool to mention that it does work for larger graphs. May4 revised Let $G$ be a connected graph. If $G$ has no cut vertices, then G has no bridges. added 15 characters in body May4 comment Let $G$ be a connected graph. If $G$ has no cut vertices, then G has no bridges. It does not. That is a counter example. May4 answered Let $G$ be a connected graph. If $G$ has no cut vertices, then G has no bridges. Feb5 awarded Popular Question Jan23 comment Integrating a Taylor series term-by-term Well you actually have 3 limits going on, so maybe its the limit of $z \to \infty$ that is resisting the swap. $$\int_0^\infty \frac{\sin x}{x} dx = \lim_{z\to\infty}\int_{1/z}^z \frac{\sin x}{x} dx = \lim_{z \to \infty}\lim_{n \to \infty}\sum_{k = 0}^n\frac{\sin x_k^*}{x_k^*} \Delta x_k^*.$$ Now using the Taylor series, we have, $$\lim_{z \to \infty}\lim_{n \to \infty}\lim_{m \to \infty}\sum_{k = 0}^n \sum_{j=0}^m \frac{(-1)^j}{(2j + 1)!} (x_k^*)^{2j} \Delta x_k^*.$$ Note: $x_k^*$ depends on $z$.