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Feb
12
comment PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
@user61933 I've edited the answer in order to address your questions. Please, if you find it appropriate, vote up and accept the answer.
Feb
12
revised PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
added 524 characters in body
Feb
12
answered PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
Feb
12
revised PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
texified it
Feb
12
reviewed Reviewed Construct a convergent series of positive terms with $\displaystyle\limsup_{n\to\infty} {a_{n+1}\over{a_n}}=\infty$
Feb
12
comment PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
I added $\LaTeX$ to your question. Please verify it's correct.
Feb
12
suggested suggested edit on PDE method of characteristics solving $e^{t^2}u_t+tu_x=0$ with $u(x,0)=x+2$
Feb
12
revised Does the limit as $(x,y) \to (1,2)$ of $3x^3-x^2 y^2$ exist?
texified it
Feb
12
suggested suggested edit on Does the limit as $(x,y) \to (1,2)$ of $3x^3-x^2 y^2$ exist?
Jan
30
revised Integral using residue theorem (maybe)
edited tags
Jan
30
answered Integral using residue theorem (maybe)
Jan
30
comment Diff eq. transformation polar coordinates
Two things. Your notation is obscure, as $t$ is function of the variable of integration, i.e. $\frac{d t}{d \xi} \equiv {t}'$, hence you are using the chain rule wrong; also, the cubic term on the second component of your substitution should read $-r^3 \sin t$. See my answer for details.
Jan
30
answered Diff eq. transformation polar coordinates
Jan
14
comment How to find the following derivative?
@LanceFerd It's the domain of definition for $\arcsin t$, i.e. the range where $\sin x$ is invertible -in the principal branch, that is-.
Jan
14
comment How to find the following derivative?
@LanceFerd One has to be carefull when taking root of a squared function: $$\sqrt{f^2(x)} = \big|f(x)\big|.$$ See my answer for details.
Jan
14
revised How to find the following derivative?
added 116 characters in body
Jan
14
comment How to find the following derivative?
@GitGud Edited. By the way, if you use \arcsin x, you produce $$\arcsin x.$$
Jan
14
revised How to find the following derivative?
added 484 characters in body
Jan
14
answered How to find the following derivative?
Jan
13
comment Wave equation solution properties
@rlgordonma I'd say that the fact that $v_{\alpha \beta} = 0$ implies that $v(\alpha,\beta) = F(\beta) + G(\alpha)$ which, in turn, means that $u(x,t) = F(x-t) + G(x+t)$ (this can be ensured because the transformation $(x,t) \to (\alpha,\beta)$ is invertible), and given that the wave equation with initial conditions has a unique solution (provided $f$ and $g$ are in some space, details left to the OP), this has to be it. Finally, using the initial conditions, one can determine $F$ and $G$ in terms of $f$ and $g$, and derive d'Alambert solution.