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| bio | website | dougtreadwell.com |
|---|---|---|
| location | Sacramento, CA | |
| age | 29 | |
| visits | member for | 2 years, 10 months |
| seen | Sep 20 '11 at 2:09 | |
| stats | profile views | 169 |
College student (CS, bio, business). Web developer.
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Sep 19 |
comment |
Do I need to understand Multi-Variable Calculus to study Linear Algebra? I think you're confusing lower division multi-variable calculus as it's taught with how you could theoretically apply it or how it is used in later courses. Knowledge of linear algebra or multi-variable calculus will not greatly effect the ease of taking the other. In the schools I looked at, multi-variable calculus is not a prerequisite for linear algebra or vice versa, which indicates that what I'm saying is correct. |
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Sep 19 |
comment |
Do I need to understand Multi-Variable Calculus to study Linear Algebra? This is exactly what I mean by coincidental overlap. That's what, 1 or 2 days out of a 90 day calculus class? |
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Sep 19 |
answered | Do I need to understand Multi-Variable Calculus to study Linear Algebra? |
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Dec 9 |
awarded | Precognitive |
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Jul 27 |
awarded | Beta |
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Jul 25 |
comment |
Does .99999… = 1? I see no proof, mathematical, logical, or otherwise, in the above. |
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Jul 23 |
awarded | Teacher |
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Jul 23 |
answered | Best Intermediate/Advanced Computer Science book |
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Jul 23 |
comment |
Does .99999… = 1? Also should be tagged "I'm going to say it's true because my teacher told me it was true", for many of the replies. |
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Jul 23 |
comment |
Does .99999… = 1? I disagree that writing 0.999... necessarily means the same thing as "lim sum(9*10^j, for j = -1 to n) as n goes to negative infinity". 0.999... is the sum, as I read it, not the limit of the sum. If you intend it to be the limit, at least write lim in front of it. You'd never be able to get away with this assumption/omission anywhere else. |
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Jul 23 |
awarded | Critic |
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Jul 23 |
awarded | Supporter |
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Jul 23 |
awarded | Editor |
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Jul 23 |
revised |
Does .99999… = 1? added 827 characters in body |
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Jul 23 |
comment |
Does .99999… = 1? 10x - x != 9. 10x - x would be 8.9999...1. However infinite the extent of 9s is in x, if we multiply it by 10, the nines are shifted left by one position and a zero inserted at the "last" place, and then when you subtract the other number there is a nine subtracted from a zero at the far right. Otherwise we'd have to give 0.999.. some unusual properties like automatically increasing the number of nines when it is multiplied. It would not be just an ordinary number. Maybe that's the problem. 0.999... might just not be an ordinary type number as some people are using it. |
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Jul 23 |
answered | Does .99999… = 1? |
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Jul 22 |
answered | How would you describe calculus in simple terms? |
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Jul 22 |
awarded | Autobiographer |
