21,010 reputation
31850
bio website maths.lth.se/matematiklth/…
location Lund, Sweden
age 42
visits member for 3 years, 1 month
seen 6 hours ago

Associate professor, Lund University. Research interests: several complex variables, in particular pluripotential theory.


2d
awarded  Constituent
2d
comment Absolutely convergent but not convergent
@Idonknow For example $a=1-1/\sqrt2$, $b=-1/\sqrt2$.
2d
answered Absolutely convergent but not convergent
2d
revised Absolutely convergent but not convergent
Typo and tag
2d
revised How can I prove $\sum_{n=1}^{\infty }\frac{1}{n^3(n+1)^3}=10-\pi ^2$
added 7 characters in body; edited tags
2d
comment Does $\displaystyle\lim_{x \to 1}x\ln(x - 1)$ exist? WolframAlpha says yes
Wolfram Alpha shows the complex valued version of $\log$.
2d
comment Need help with holomorphic functions on a domain interval removed.
See also this question for something very similar.
Dec
18
revised Bounded functions composed with Möbius maps
Fixed spelling of Möbius
Dec
18
answered Bounded functions composed with Möbius maps
Dec
18
answered Help with simplification of an expression
Dec
18
answered Can two analytic functions that agree on the boundary of a domain, each from a different direction, can be extending into one function?
Dec
18
comment Need help with holomorphic functions on a domain interval removed.
This is related to something called (continuous) analytic capacity. If there is no answer, I'll post something when I have more time.
Dec
18
comment Prove that a intergral over $\mathbb R$ is finite
The last inequality in the second displayed formula looks suspicious. ($|f(s)|$ is only small when $|s|$ is large, and you are integrating over all of $\mathbb{R}$)
Dec
18
answered Prove that a intergral over $\mathbb R$ is finite
Dec
17
comment an analytic function in $\Delta^n$ is bounded in $T^n$, then it is bounded in $\Delta^n$
That's what I said in my last sentence. What do you mean by "bounded on $T^n$" if the function is only defined on (the open set) $\Delta^n$? (I.e. what kind of boundary values do you mean?)
Dec
17
reviewed Leave Open Show that a function from a set is non-conservative
Dec
17
comment Why is it sometimes it seems like you can integrate with respect to x or y and treat the other as a constant, and other times you can't?
@Celeritas Solving an exact equation, you're looking for a solution of the type: "$f(x,y) = C$", which defines $y$ implictly in terms of $x$ or vice versa. Usually when you are solving an ODE you are looking for an explicit solution $y(x)$.
Dec
17
answered Why is it sometimes it seems like you can integrate with respect to x or y and treat the other as a constant, and other times you can't?
Dec
17
comment Integral of rational function in the complex plane
See this question for a near duplicate
Dec
16
reviewed Close If $H<S_n$, $H$ is abelian and transitive on $\{1,2,…,n\}$, then the order of $H$ is $n$