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An expert is a man who has made all the mistakes, which can be made, in a very narrow field. (Niels Bohr)


Oct
29
reviewed Approve suggested edit on The number of non-negative integral solutions to the equation $4x_1+x_2+x_3=n$
Oct
29
reviewed Leave Open Sum of positive definite matrices still positive definite?
Oct
29
revised how to prove $(-1)\cdot(-1)=1$ based only on the field axioms?
deleted 30 characters in body
Oct
29
revised True or false: $a^2+b^2+c^2 +2abc+1\geq 2(ab+bc+ca)$
edited title
Oct
29
revised how to prove $(-1)\cdot(-1)=1$ based only on the field axioms?
deleted 225 characters in body
Oct
29
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
deleted 10 characters in body
Oct
29
reviewed Close Prove by induction that $1^3 + 2^3 + 3^3 + …+ n^3= \frac{n^2(n+1)^2}{4}$ for all $n\geq1$.
Oct
29
comment Implicit derivitave of a general ellipse
It makes no sense to say 'derived from ellipse'. Derivatives are defined only for functions. I imagine you want to get the implicit differentiation from (this is also something well defined) the ellipse equation.
Oct
29
revised Implicit derivitave of a general ellipse
added 13 characters in body
Oct
29
reviewed Approve suggested edit on How to document undergrad math knowledge?
Oct
28
revised Intuitive explanation of sum^2
added 6 characters in body
Oct
28
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
deleted 5 characters in body
Oct
28
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
added 10 characters in body
Oct
28
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
added 383 characters in body
Oct
28
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
added 299 characters in body
Oct
28
answered limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
Oct
28
revised limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
edited title
Oct
28
reviewed Approve suggested edit on limit of $u_n = u_{n-1}\cdot \frac{n}{n+1}$ and $v_n = v_{n-1}\cdot \frac{n+1}{n}$
Oct
28
answered $\inf$ and $\sup$ of the following sets
Oct
28
reviewed Close Simplifying the infinite series $\sum_{n = 1}^{\infty} \left(\frac{1}{2}\right)^{3n}$