Reputation
Top tag
Next privilege 5,000 Rep.
Approve tag wiki edits
Badges
3 21 50
Impact
~104k people reached

Feb
7
awarded  Notable Question
Jan
29
awarded  Good Question
Dec
27
awarded  Good Question
Dec
4
asked Closed form for $\int_0^{\pi/2} \log\bigl( g(x) \bigr) f(n x) \,\mathrm{d}x$
Dec
4
accepted Share the beer fairly in a finite number of pours
Nov
28
awarded  Nice Answer
Nov
27
answered Odd function in an integral
Nov
27
awarded  Popular Question
Nov
25
asked Is the transformation between these two functions smooth?
Nov
25
revised Closed form of the integral
added 253 characters in body
Nov
25
revised Closed form of the integral
deleted 25 characters in body
Nov
25
answered Closed form of the integral
Nov
24
comment Closed form of the integral
Why do you think the integral has a closed form? Where does it come from? ...
Nov
22
answered Solving the integral $\int_{-1}^1 2\sqrt{2-2x^2}\,dx$
Nov
18
comment Calculate $\int_0^{2\pi}\int_0^b \frac{r}{a-r\cos \vartheta}dr\,d\vartheta$.
Are we sure this integral actually converges? To me it seems to blow up quite badly.
Nov
17
awarded  Good Answer
Nov
17
awarded  Notable Question
Nov
16
comment Improper integral:- Change of Variable.
Yes. How does you prove the identity $\int_a^b f(x)\,\mathrm{d}x = \int_a^b f(a+b - x) \,\mathrm{d}x$? One way is to use the substitution $x \mapsto a + b - u$ which only makes sense mathematically when $a$ and $b$ are real numbers. Lets for simplicity sake say that $a=0$. Then $\int_0^a f(x) = \int_0^a f(a-x)$. Geometrically we now integrate backwards starting at $a$ and working backwards untill zero, this notion of backwardness (or symetry around $(a+b)/2$) loses all meaning when we include infinity.
Nov
16
comment Improper integral:- Change of Variable.
Do you want to know how to calculate this integral? (I have it in my notes) Or do you wonder why you can not always apply the $f(x) = f(a + b - x)$ property? The last follows from that you need to integrate over a finite interval to give meaning to reflection.
Nov
5
comment figure out $\int_{-\pi}^{\pi}\frac{ab}{a^2\cos^2 t+b^2\sin^2 t}\,dt$
Duplicate${}{}{}$