3,420 reputation
11041
bio website
location Ntnu Gløshaugen, Norway
age
visits member for 2 years, 11 months
seen 3 hours ago

Studying to be a teacher and obtain a degree in mathematics.


Oct
14
accepted Prove that $\int_{-\infty}^{\infty} \frac{e^{2x}-e^x}{x (1+e^{2x})(1+e^{x})}\mathrm{d}x$ equal $\log 2$
Oct
11
comment Books with collections of unusual and advanced integration techniques
Some of my notes folk.ntnu.no/oistes/Diverse/Integral%20Kokeboken.pdf =)
Oct
10
revised Proving the natural log inequality $\frac{3}{4} < \frac{1}{\sqrt{3}} \log(2 + \sqrt{3}) < \frac{\pi}{4}$
edited title
Oct
10
asked Proving the natural log inequality $\frac{3}{4} < \frac{1}{\sqrt{3}} \log(2 + \sqrt{3}) < \frac{\pi}{4}$
Oct
8
comment Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
math.stackexchange.com/questions/61605/… If you want further discussion ping me in chat.
Oct
8
comment Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
Someday ;)${}{}{}$
Oct
8
comment Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
@Anastasiya-Romanova Thanks, the problem will be placed in here eventually ^^ folk.ntnu.no/oistes/Diverse/Integral%20Kokeboken.pdf
Oct
7
comment Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
Your answer was the first I got, andthe first one I used. However for later readers who also stumble uppon this integral I feel the answer given by Anastasiya is clearer.
Oct
7
accepted Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
Oct
7
comment Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
Oh I am. I have a habit of waiting a few days, and it just so happened a flu struck. Been lying in bed for a few days or so
Oct
2
awarded  Necromancer
Oct
2
awarded  Nice Question
Oct
2
revised Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
added 125 characters in body
Oct
2
revised Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
added 4 characters in body
Oct
2
asked Prove that $ \int_0^{\pi} \frac{(\cos x)^2}{1 + \cos x \sin x} \,\mathrm{d}x =\int_0^{\pi} \frac{(\sin x)^2}{1 + \cos x \sin x} \,\mathrm{d}x $
Sep
24
awarded  Autobiographer
Sep
18
accepted Closed form for $\int_0^x \{1/t \}\,\mathrm{d}t$, $x \in \mathbb{R}_+$ and related.
Sep
3
comment Resources for Integrals?
Maybe this can be of some assistance, www.folk.ntnu.no/oistes/Diverse/Integral Kokeboken.pdf if you dissregard the alien language.
Sep
2
comment infinite integral of $\frac{1}{1+x^n}$
duplicate ${}{}{}$
Aug
29
awarded  Necromancer