103 reputation
3
bio website klickverbot.at
location Austria
age
visits member for 2 years, 5 months
seen Nov 27 '13 at 3:14

Aspiring student, interested in way to many things.


Mar
24
awarded  Scholar
Mar
24
accepted Proving $(f^{-1}(U))^0 = f^*(U^0)$
Mar
15
awarded  Supporter
Mar
15
comment Proving $(f^{-1}(U))^0 = f^*(U^0)$
I think ${(U^0)}^0 \cong U$ only holds in the finite dimensional case. Also – sorry for that – I edited the question removing the requirement that V and W be Euclidean, since I really want to prove the general case (it just happens that the only application I have for it right now deals with Euclidean spaces). I think, though, that the proof might still work with minor modifications, let me check…
Mar
15
revised Proving $(f^{-1}(U))^0 = f^*(U^0)$
deleted 3 characters in body
Mar
15
revised Proving $(f^{-1}(U))^0 = f^*(U^0)$
added 2 characters in body
Mar
15
awarded  Editor
Mar
15
comment Proving $(f^{-1}(U))^0 = f^*(U^0)$
@ArturoMagidin, Benjamin Lim: Clarified the question.
Mar
15
revised Proving $(f^{-1}(U))^0 = f^*(U^0)$
added 166 characters in body
Mar
15
asked Proving $(f^{-1}(U))^0 = f^*(U^0)$