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 May 4 comment About primes and Euler's totient function. If I have read this correctly then if you change less than to less than or equal to then it will be trivially true? Any prime, $p$, less than n had $gcd(p,n)=1$ and so if we denote the set of integers than are less than $n$ as and reletively prime to $n$ then any prime p less than $n$ will be in $X$ and we are done. May 2 comment If a group G is isomorphic to H, prove that Aut(G) is isomorphic to Aut(H) This question isn't really that clear. Are you attempting to suppose that $H$ and $G$ are isomorphic and then show that $Aut(G)$ and $Aut(H)$ are isomorphic? Dec 2 comment Finding the Dual of a primal LP @calculus No dimensions given but I don't see why that would be relevant? Also is what I have done not correct, I think I have it? Nov 26 comment How to convert to conjunctive normal form? @moose just type it on in: wolframalpha.com/input/… Oct 13 comment Proof of Simplex Method, Adjacent CPF Solutions @stefanos yeah i was kind of wondering how exactly to go about showing this though? Aug 19 comment If G is a group of order n=35, then it is cyclic @JoeDub I'm slightly confused. I have assumed that $|G|=pq$ and so all elements must be of finite order? Jun 22 comment Axiom of Limitation of Size Reference Request Thanks, I managed to track down a reference to von Neumann's collected works, I imagine it would be far to convenient if there happened to be a translation somewhere May 23 comment Showing that $\mathbb{R}\times [0,1]$ is quasi-isometric to $\mathbb{R}$ @DanielFischer Just the standard metric (euclidean) I think as it is not specified. May 23 comment Showing that $\mathbb{R}\times [0,1]$ is quasi-isometric to $\mathbb{R}$ @drhab I have edited in the definition of quasi-isometric, does this help? May 22 comment Do we sometimes have to go “each way” separately for iff proofs? I find this question interesting, although it may have a simple answer, I could imagine there being some crazy counterexample- I'm thinking of some sort of independence proof? May 22 comment Showing that triangles in $\mathbb{Z}$ are thin @DerekHolt Ah yes of course, thanks for the help! :) If you wish to post as an answer I would gladly accept May 22 comment Showing that triangles in $\mathbb{Z}$ are thin @DerekHolt thanks. Could you explain your first line a bit please? May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint OK, but how do I go about doing this? May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint Is there no way I can do this with intermediate value theorem like you suggested? Something like taking a $\gamma_3$ that intersects $\gamma_2$ perpendicularly and then vary the endpoints of $\gamma_3$ somehow to get the intersection with $\gamma_1$ to be perpendicular? May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint I'm not sure sorry, my basic algebra is pretty bad! How do I calculate that? May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint Sorry I is quite hard to explain what I mean without pictures! May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint My geodesics are circles that intersect the boundary perpendicularly so I was being stupid taking straight line not through the center as it does not intersect perpendicularly sorry. So do I take $\gamma_3$ which intersects $\gamma_2$ perpendicularly. Then vary the other endpoint and by IVT there will be a point which intersects $\gamma_1$ perpendicularly. May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint Ok so I say that $\gamma_1$ is the horizontal line through the origin and take $\gamma_2$ such that they don't share endpoints on $S_\infty$. Now I need to find geodesic intersecting them both perpendicularly. So any vertical line will intersect $\gamma_1$ perpendicularly can I then show that it intersects $\gamma_2$ perpendicularly at some point? May 19 comment Showing geodesics in $\mathbb{H}^2$ have unique common perpendicular or common endpoint No I am using the interior of the unit disc in $\mathbb{R}^2$ sorry I should have mentioned that I will edit my question May 16 comment Baumslagâ€“Solitar $B(1,2)$ is not hyperbolic @N.Owad No, could you give me reference/ explain to me?