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location United Kingdom
age 23
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Currently studying for an Msc in Mathematics


Apr
21
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
Sorry, I thought the bounty was awarded automatically when I accepted an answer, I have awarded it now. Thanks for the help! :)
Apr
19
awarded  Quorum
Apr
19
revised Proving that $V(R^*)=V(R)-1$
edited title
Apr
19
revised Proving that $V(R^*)=V(R)-1$
added 3 characters in body
Apr
19
asked Proving that $V(R^*)=V(R)-1$
Apr
18
accepted Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
@rschwieb Right ok, I'll have a play around with that to check that I get everything. Thanks everyone for the help!
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
@rschwieb Cool, could you possibly explain the set where we assume that $(a)^2(b)^3\subset RaRbR$? I can't see why this follows? Thanks
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
That is if $1\notin R$ then surely we do not need to have $a\in aR$ or $b\in bR$?
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
How did you conclude that $(a)^2(b)^3\subseteq RaRbR$?
Apr
17
revised Can these two quotient groups be isomorphic?
added 792 characters in body
Apr
17
answered Can these two quotient groups be isomorphic?
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
@ah11950 It does indeed!
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
@rschwieb No sorry the question is not online, I shall email my lecturer and hope that he gets back to me.
Apr
17
comment Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
@ah11950 I believe we are/have taking/taken the same course!
Apr
15
asked Equivalence Of Definitions Of Prime Ideal In Ring Without $1$
Apr
14
comment Modern book on Gödel's incompleteness theorems in all technical details
I think that Peter Smyth's book is pretty good, logicmatters.net/igt
Apr
11
comment Proving The Diamond Lemma
@fgp Sorry that was meant to be $P$. Yeah I think it's an induction step with a subtlety about making sure chains stop after nice numbers of steps or something, however the way I am asked to answer this question is using this $Q(a)$ and I have no idea where to proceed with it, every time I do I just end up back at the induction.
Apr
11
revised Proving The Diamond Lemma
edited body
Apr
11
comment Proving The Diamond Lemma
@fgp but condition 2) only applies if $a\rightarrow b_1$ and $a\rightarrow b_2$. If we have a chain $a\rightarrow a_1 \ldots \rightarrow b$ then we would need to apply condition 2) to each step of the chain right? I think that is what this $Q(a)$ is attempting to avoid?