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 Apr 29 awarded Notable Question Feb 19 awarded Nice Question Feb 2 awarded Nice Answer Jan 25 awarded Nice Question Jan 6 awarded Nice Question Jan 6 awarded Nice Question Dec 29 accepted Intuition for Kähler manifolds? Dec 27 revised Algebraic methods to compute the cohomology ring of the complex topology of a variety? edited tags Dec 27 comment Intuition for Kähler manifolds? @GunnarÞórMagnússon I think that is conceptually the clearest explanation. If you post it as an answer, I would be happy to accept it! Dec 3 awarded Popular Question Nov 11 comment Is there a proof of Bézout's theorem via residue theory? @TakumiMurayama Actually I think I'm being really stupid. Consider for example $f_1 = x, f_2 = y$. in $\mathbb P^2$. We have the right residue at $0$, and then I think we pick up the extra stuff when we switch charts and consider the line at infinity, so it all works out. The sum is zero, but one of the terms is exactly what we want, so we can just rearrange and get Bezout. Nov 11 awarded Nice Question Nov 11 comment Is there a proof of Bézout's theorem via residue theory? @TakumiMurayama So the global residue theorem is on p. 656, I think. But now I'm confused about something simple: the residue theorem says a certain sum is zero, but we want a sum that equals $\Pi d_i$. In particular, if we take the form to be $\frac{df_1}{f_1}\wedge\dots\wedge \frac{df_i}{f_i}$, doesn't the global residue theorem tells us the sum of the residues is $0$ and not the product of the degrees, as we desire? Nov 8 awarded Nice Answer Nov 6 awarded Necromancer Nov 4 awarded Notable Question Oct 29 awarded Popular Question Oct 25 awarded Yearling Oct 24 comment Other ways to compute this integral? @Unit You did the straightforward thing. I don't see anything wrong with that aesthetically. Oct 24 comment Unconventional mathematics books Mumford wrote approvingly of this book in his Notices article "Calculus Reform--For the Millions."