3,348 reputation
2826
bio website
location
age
visits member for 2 years, 10 months
seen 2 hours ago

Jul
19
comment Euclid's proof of the infinitude of primes to prove this question
@MichaelHardy: Your comment surprised me. I understand that $S$ is then extended to a larger finite set of primes. If it is error to call it a proof by contradiction it is a common error. Would you mind elaborating briefly?
Jul
17
revised Start studying mathematical biology from basics
added 257 characters in body
Jul
17
answered Start studying mathematical biology from basics
Jul
15
awarded  Notable Question
Jul
9
comment Are NSA Mathematicians second-rate?
This doesn't seem to be about math.
Jul
9
revised Asymptotic density of powers of primes
deleted 65 characters in body
Jul
8
revised Asymptotic density of powers of primes
added 127 characters in body
Jul
8
revised Asymptotic density of powers of primes
added 332 characters in body
Jul
8
revised Asymptotic density of powers of primes
deleted 16 characters in body
Jul
8
revised Asymptotic density of powers of primes
added 31 characters in body
Jul
8
revised Asymptotic density of powers of primes
added 1 character in body
Jul
8
revised Asymptotic density of powers of primes
added 155 characters in body
Jul
8
revised Asymptotic density of powers of primes
added 1 character in body
Jul
8
comment Asymptotic density of powers of primes
Well--not so sure. $\pi(11) = 5.$ But we have $2,2^2,2^3,3,3^2,5,7,11$ or cardinality of 8...?
Jul
8
revised Asymptotic density of powers of primes
added 18 characters in body
Jul
8
answered Asymptotic density of powers of primes
Jul
8
comment Asymptotic density of powers of primes
That's how I understand it although I am not familiar with $\Pi(x)$ in that form. It is the cardinality of the set of powers of primes less than or equal to x. At least that's how it looks to me.
Jul
8
comment Asymptotic density of powers of primes
Under the Wiki entry for Prime Number Theorem, Chebyshev's $\psi(x) = \sum_{p^k \leq x} \log p$ is asymptotic to x. Comparing this to your $\Pi(x)$ would seem to confirm Antonio Vargas' answer and I think give a proof. You should write $\psi(x)$ as a product.
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive