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seen Jul 18 at 19:39

Dec
31
awarded  Nice Answer
Dec
14
answered Convergence of series involving iterated $ \sin $
Oct
15
awarded  Yearling
Nov
2
awarded  Necromancer
Oct
15
awarded  Yearling
Sep
7
comment How may I prove this inequality?
Someone calls this method "uvw" downloadable here artofproblemsolving.com/Forum/…
Sep
7
answered Compute $ \int_{0}^{1}\frac{\ln(x) \ln^2 (1-x)}{x} dx $
Sep
2
comment proving :$\frac{(ab+b)(2b+1)}{(ab+a)(5b+1)}+\frac{(bc+c)(2c+1)}{(bc+b)(5c+1)}+\frac{(ca+a)(2a+1)}{(ca+c)(5a+1)}\ge\frac{3}{2}$
It comes from here fen.bilkent.edu.tr/~cvmath/Problem/problem_2011.htm (April 2011)
Aug
30
answered Inequality $(a+\frac{1}{b})^2+(b+\frac{1}{c})^2+(c+\frac{1}{a})^2\ge 16$
Jun
21
answered Linear change of variables in Hamiltonian functions
Jun
19
answered Question on sequences
Jun
19
answered infinite series involving harmonic numbers and zeta
Jun
14
answered Calculate alpha from $\alpha + \sin(\alpha)$ = K
Jun
14
comment An inequality involving integrals
@Mohamed: <<....function $x↦6x−2=3(2x−1)$ used...>>??
Jun
14
awarded  Supporter
Jun
14
answered An inequality involving integrals
Jun
14
comment Convergence of a function series
The general term may well be not positive: put a minus sign in front of the series. As for the monotonicity, note that $$ \left(\frac 1t\ln \frac xt\right)' =\frac{\ln t}{t^2} -\frac{1+\ln x}{t^2}$$ so is asymptotically incresing. The assumption are satisfied except at most for a finite number of terms but this doesn't affect the convergence
Jun
13
answered Convergence of a function series
Jun
12
answered Computing $\sum_{n=0}^{\infty} u_{n}, \frac{u_{n+1}}{u_n}=\frac{n+a}{n+b}$
Jun
9
revised abel summable implies convergence
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