108 reputation
4
bio website blog.bitsrc.org
location Vienna, Austria
age
visits member for 2 years, 10 months
seen Dec 25 '13 at 21:52

Apr
18
awarded  Scholar
Apr
18
accepted Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
Oct
15
awarded  Student
Oct
15
comment Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
How does it follow that the inequality is true for n=2 where obviously the statement isn't, but false at n=1 where the statement is? bit.ly/ndBnQX
Oct
15
comment Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
Also, that it's false for n = 2 makes me wonder how any proof that does not take that into account can be correct.
Oct
15
comment Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
I have tried it out before and found out it is true for n ≥ 3 (or in fact, for n ≠ 2).
Oct
15
revised Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
added 2 characters in body
Oct
15
revised Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
edited title
Oct
15
awarded  Supporter
Oct
15
comment Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
Aaah excuse me, I truncated two characters when I copied the formula, it's updated now. Should be clear now too. Sorry.
Oct
15
revised Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
edited title
Oct
15
comment Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
I can assure you I was assigned the problem. Clarified that I only need natural numbers; Also good but not perfect would be a proof that it's true for n ≥ 3.
Oct
14
awarded  Editor
Oct
14
revised Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$
edited title
Oct
14
asked Prove for which $n \in \mathbb{N}$: $9n^3 - 3 ≤ 8^n$