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Dec
8
revised Evaluate $\int\sqrt[5]{\frac{x+5}{x-5}}\,\mathrm dx$
added 41 characters in body
Dec
8
asked Evaluate $\int\sqrt[5]{\frac{x+5}{x-5}}\,\mathrm dx$
Dec
8
accepted How to show this $\lim_{n\rightarrow\infty} {\sqrt[n]{1+n^2}} =1$
Dec
8
accepted Series convergence of $\sum_1^\infty\frac{(n!)^2+(2n)^n}{n^{2n}}$
Dec
6
asked Series convergence of $\sum_1^\infty\frac{(n!)^2+(2n)^n}{n^{2n}}$
Dec
1
comment Roots of $x^4 -6x^3 +x^2+10x +1=0$
how did you get f(x) ?
Dec
1
accepted Roots of $x^4 -6x^3 +x^2+10x +1=0$
Dec
1
comment Roots of $x^4 -6x^3 +x^2+10x +1=0$
thanks I was confused with Rolle theorem
Dec
1
asked Roots of $x^4 -6x^3 +x^2+10x +1=0$
Nov
28
accepted Point of inflection and third derivative
Nov
28
comment Point of inflection and third derivative
Well what has confused me in first place was its example where it finds f''(2)=0 for a point so they check the third f'''(2)=6 and since its !=0 it states that it is a inflection point . But this doesnt have any relation with the statement...
Nov
28
comment Point of inflection and third derivative
So are you 100% sure that book is wrong?
Nov
28
asked Point of inflection and third derivative
Nov
25
comment Compute limit $\lim_{n\rightarrow\infty}\frac{1*3*5*…*(2n-1) }{ 2*4*6*…*(2n)}=0$
the one in the body
Nov
25
asked Compute limit $\lim_{n\rightarrow\infty}\frac{1*3*5*…*(2n-1) }{ 2*4*6*…*(2n)}=0$
Nov
24
asked Series comparison test for $ \sum_1^\infty n^{\ln(n)} \ln(n^n)$
Nov
24
asked How to show this $\lim_{n\rightarrow\infty} {\sqrt[n]{1+n^2}} =1$
Nov
10
accepted $ \sum_1^\infty (-1)^n \left(1 + \frac{2}{n^2}\right)^{n^2} $ series diverge
Nov
10
comment $ \sum_1^\infty (-1)^n \left(1 + \frac{2}{n^2}\right)^{n^2} $ series diverge
@BrianM.Scott yes.However according to what I know we cant tell for sure about Series. (only in case sequence limit is zero
Nov
10
comment $ \sum_1^\infty (-1)^n \left(1 + \frac{2}{n^2}\right)^{n^2} $ series diverge
I know the limit is $e^2$ But how does this help