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1d
comment Root with bolzano theorem
cause theory has < . it makes sense but formally not
1d
asked Root with bolzano theorem
1d
accepted Limit find $f(x)$ $ \lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3 $
1d
comment Limit find $f(x)$ $ \lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3 $
Just solving some before LHospital problems and want to learn without it too...
1d
comment Limit find $f(x)$ $ \lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3 $
It seems the key was there to change cos to sin. I should have thought it...
1d
comment Limit find $f(x)$ $ \lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3 $
hm yep, however I have added without l'Hospital tag. Any idea there ?
1d
asked Limit find $f(x)$ $ \lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3 $
1d
accepted Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
1d
comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
I am going to ask why it is poor but probably he isnt going to tell me(cant insist he'll get annoyed).However after asking lots of other classmates someone showed me the solution . It is like this math.stackexchange.com/a/493782/17446 .
2d
comment Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
seems possible but hard
2d
comment Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
very smart... wow
2d
accepted Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
2d
comment Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
yes I am sure...
2d
comment Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
Sorry but without this
2d
asked Limit evaluation $\lim_\limits{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$
2d
comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
I have solutions which are fine but are not acceptable from professor. (I study computer science)
2d
comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
Yes it is pointless. However in case I get a solution I'll share it.
2d
comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
I dont know he didnt tell me.Maybe he is going to tell me but I am not sure if he will. In case I'll post it. I'll show him this again...
2d
comment How to prove that if $\sum_{n=0}^{\infty}a_n$ absolutely convergent $\Rightarrow \sum_{n=0}^{\infty}(a_n)^2$ convergent
why does sum raised at power is larger than $|a_k|^2$?
2d
comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$
did you figured out randomly the $ a_n^2 \leq |a_n|(\sum_1^\infty|a_n|)$?