GorillaApe
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 Feb 11 comment Sequence $a_{n+1}=\sqrt{1+\frac{1}{2}a_n^2}$ Some who doesnt know the master theorem is there an alternative solution ? Feb 10 comment Sequence $a_{n+1}=\sqrt{1+\frac{1}{2}a_n^2}$ the problem isnt for a_{n+1) -2 but for first n=1 Feb 10 comment Sequence $a_{n+1}=\sqrt{1+\frac{1}{2}a_n^2}$ for which one ? Feb 5 comment Calculate this limit $\lim_{n\to \infty } \, \frac{(-1)^n \left(n^2 \sin (n)+2 n\right)}{{n^2}+3}$ It seems it doesnt however problem asks to be found. So I guess I have to proove that it doesnt exist Feb 5 comment Integral $\int{\frac{x^5}{\sqrt{x^2+7}}}dx$ after posting this I though of using this transform. I am trying it now.. Feb 4 comment Integal $\int\left(\sqrt{4-9x^2}\right)^3 dx$ I had this in mind but seemed complex. Maybe there other substitutions too.. (initial) Feb 3 comment Limit of sequence 3 It seems that taking root test for series works. Do root test and take $7^n$ out .Then limit to ifninity of $\sqrt[n]{1+n/7^n}$ should be 1. Feb 3 comment Integral proof $I_n=\int\frac{x^n}{\sqrt{x^2+5}} \, dx$ SebiSebi suggestion helped me to solve it Feb 3 comment Integral proof $I_n=\int\frac{x^n}{\sqrt{x^2+5}} \, dx$ its a everywhere Feb 3 comment Taylor Series $(x+2)/(2-3x)$ at $x=2$ according to wolfram alpha it seems that $3^n$ should be $3^{n+1}$ Feb 3 comment Taylor Series $(x+2)/(2-3x)$ at $x=2$ to those who want to close this why?. Feb 2 comment Find monotony of $f(x)=x^5 +x^4 -11x^3 + 9x^2$ @namsap because it isnt easy to find roots for derivative Feb 1 comment How to find $\lim_{x\to\infty}{\frac{e^x}{x^a}}$? Why is it correct to take log ? Jan 27 comment Root with bolzano theorem cause theory has < . it makes sense but formally not Jan 27 comment Limit find $f(x)$ $\lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3$ Just solving some before LHospital problems and want to learn without it too... Jan 27 comment Limit find $f(x)$ $\lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3$ It seems the key was there to change cos to sin. I should have thought it... Jan 27 comment Limit find $f(x)$ $\lim_{x\to1}\frac{f(x)\cos{\frac{\pi x}{2}}}{\sqrt[3]x-1}=3$ hm yep, however I have added without l'Hospital tag. Any idea there ? Jan 27 comment Series proof $\sum_1^\infty|a_n|<\infty$ then show that $\sum_1^\infty{a_n^2}<\infty$ I am going to ask why it is poor but probably he isnt going to tell me(cant insist he'll get annoyed).However after asking lots of other classmates someone showed me the solution . It is like this math.stackexchange.com/a/493782/17446 . Jan 26 comment Limit evaluation $\lim_{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$ seems possible but hard Jan 26 comment Limit evaluation $\lim_{x\to2}\frac{\sqrt{12-x^3}-\sqrt[3]{x^2+4}}{x^2-4}$ very smart... wow