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1d
comment Is every shape possible with a snake?
there are some small legal moves by folding just a tiny part at the tail/head of the snake. Though there shouldn't be enough room to squeeze everything away. (and just now i understand the "horizontall ines are 1 unit apart line)
2d
awarded  Yearling
Jan
24
comment Is this approach to the Collatz conjecture flawed?
no, you can't prove the collatz conjecture with 2 pages of random reformulations and modulo arithmetic.
Jan
23
comment Construct a set of real numbers whose limit points comprise the set of integers $\mathbb{Z}$
"and it actually does not contain any integers" eeerr what about when $n=1$
Jan
16
comment What is the exact value of $\sqrt{-3+2\sqrt{-5+3\sqrt{-7+4\sqrt{-9+\dots}}}}$
the page talks about nested radicals with positive terms, which is obviously not the case here
Jan
16
comment What is the exact value of $\sqrt{-3+2\sqrt{-5+3\sqrt{-7+4\sqrt{-9+\dots}}}}$
@Mathematician171 : this $R$ is not an expression that makes sense as it is. Maybe you should talk about the limit (if it exists) of some sequence of numbers like GEdgar did in his answer, but for now we have NOTHING to talk about.
Jan
16
comment What is the exact value of $\sqrt{-3+2\sqrt{-5+3\sqrt{-7+4\sqrt{-9+\dots}}}}$
this is very similar to math.stackexchange.com/questions/501047/…
Jan
16
comment Is $\sqrt[3]{5}$ in $\mathbb Q(\sqrt[3]{2})$?
I don't think this works if the coefficients of $\sqrt[3]5$ are rationals with some $p$ in their denominator. That's why i went to the trouble of restricting the possible denominators. Sure there are an infinite number of primes like that but that's a bit more high level.
Jan
16
answered Is $\sqrt[3]{5}$ in $\mathbb Q(\sqrt[3]{2})$?
Jan
16
accepted Are the discriminant of abelian cubic extensions of $\Bbb Q$ equal to the square of their conductor?
Jan
14
asked Are the discriminant of abelian cubic extensions of $\Bbb Q$ equal to the square of their conductor?
Jan
14
comment Show that $\hat{E}\setminus E$ is homeomorphic to $S^1$
the points equidistants to $y_1$ and $y_2$ form a line called the bissector of $y_1$ and $y_2$.
Jan
14
answered Show that $\hat{E}\setminus E$ is homeomorphic to $S^1$
Jan
12
awarded  Nice Answer
Jan
12
comment Radical extension and discriminant of cubic
if $\Delta$ is a square there is no quadratic subfield (either the extension is cyclic or it is trivial), so it can't contain $\sqrt{-3}$
Jan
12
answered Why doesn't every integral from 0 to $2\pi$ equal zero?
Jan
12
comment Radical extension and discriminant of cubic
because $3 = [\Bbb Q(\alpha) : \Bbb Q]$ and usually $n = [\Bbb Q(\sqrt[n]a) : \Bbb Q]$
Jan
12
answered Radical extension and discriminant of cubic
Jan
9
answered Show that $\sqrt[3]{3\sqrt{21} + 8} - \sqrt[3]{3\sqrt{21} - 8} = 1$
Jan
9
comment Show that $\sqrt[3]{3\sqrt{21} + 8} - \sqrt[3]{3\sqrt{21} - 8} = 1$
$(\frac {1 \pm \sqrt{21}}2)^3 = 8 \pm 3\sqrt{21}$. Also see math.stackexchange.com/questions/374619/…