# Xabier Domínguez

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University of CoruĂ±a, Spain

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 Oct10 awarded Yearling Oct10 comment Relation between a random variable and its conditional expectation For each event $G$, $X|G$ is a different random variable. If by "when $X=0$" you mean that you are considering the random variable $X|[X=0],$ that is a "constant random variable" (i. e. it takes only one value) and indeed, its expectation is zero. But this does not mean that $E(X)=0,$ nor that these considerations will help you in evaluating $P[Y\ne 0|X=0]$. Oct10 comment Semigroup question what about "constant transformation"? Oct10 comment Relation between a random variable and its conditional expectation "when $X=0$ its conditional expectation is 0 too"... whose conditional expectation? Oct10 awarded Yearling Jun27 comment Existence of measures assigning positive values to all open sets At least if $K$ is a topological group, the answer is yes: Haar measure on $K$. Jun13 answered showing a set is not a subgroup Jun8 awarded Constituent Jun8 awarded Caucus May12 suggested suggested edit on Set of all injective functions $A\to A$ May12 answered Error analysis - Bisection algorithm May11 comment How to prove the Closed map lemma Also, you should replace "sequence" with "net" since you don't assume metrizability. The argument works all the same. May11 revised Proving that an embedding $G \hookrightarrow BC(G)$ is continuous. I added a bit more of information May11 comment Exponential group? ;) You cannot go very far without it. May11 comment Exponential group? You can have nonabelian groups. The main problem is that $\uparrow$ is not associative. May11 answered Proving that an embedding $G \hookrightarrow BC(G)$ is continuous. May11 revised How to approach convergence $n!/n^n$ to infinity TeX added May11 answered How to approach convergence $n!/n^n$ to infinity May11 suggested suggested edit on How to approach convergence $n!/n^n$ to infinity May11 answered Probability rules with two conditionals only