Jose Garcia
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 Oct 9 comment inverse function , asymptotics .. yo mean $e_{relative}= e_{real}-e_{error}/e_{real}$ and $e_{absolute}= e_{real}-e_{error}$ ?? thanks for your answer fgp Oct 8 comment solving this recurrence equation f(x) is of the order $f(x)= O(x^{a})$ at least for big 'x' and an integer positive 'a' Oct 8 comment What prime number generating algorithms are used? but shouldn't better to generate primes AT RANDOM ??¿ i mean if i were a 'hacker' i first would study all the prime generating algorithms to crack codes :D :D so perhaps a prime-generating algorithm is not quite safe. Oct 3 comment inverse function and positivity you can always DRAW an inverse for any function at least for piecewise continous function, so there is always an inverse Oct 3 comment inverse function and positivity thanks Bernhard.. however if we assume $f(x)=f(-x)$ i think i this case we could always take the positive branch of the function Sep 24 comment Bessel and cosine function identity formula OK thaks to oen and Mhenni i messed myself up :D with the power series :D and all the stuff.. Sep 13 comment evaluation of the integral $\int_{0}^{x} \frac{\cos(ut)}{\sqrt{x-t}}dt$ oh sorry i wanted to write 'evaluation' instead of convergence :D ca someone edit the title ? Sep 13 comment evaluation of the integral $\int_{0}^{x} \frac{\cos(ut)}{\sqrt{x-t}}dt$ aha.. yes Babak nice edit Aug 27 comment root-finding methods to invert numerically a function thanks a lot vanna :D Aug 27 comment Delta function question $\delta (-a)=0= \delta (\infty-a)$ and $f(a)= \infty = g(1/a)$ Aug 8 comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$ anyway thank you all for your answers :D Aug 8 comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$ shouldn't it be $\frac{\pi }{2} J_{0}(au/2)$ due to the change of variable $t \rightarrow t/2$ Aug 8 comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$ aja, thanks what bessel function if possible :) thanks again Aug 8 comment Riemann Siegel formula modification? yes intx is integer part (or floor function) of 'x' i did not know how to put it Jul 31 comment evaluation of $\operatorname{Arg}\zeta (1/2+is)$ ?? umm is there or are there graphics for $arg\zeta (1/2+it)$ or graphical representaiton of the function $S(T)= \frac{1}{\pi}arg\zeta (1/2+iT)$ for several values of T , can i see or evaluate the eigenvalue staircase for teh Riemann zeros ?? Jul 31 comment evaluation of $\operatorname{Arg}\zeta (1/2+is)$ ?? but preciselyt this theta functio n $\theta (t)$ is just the smooth part of the zeros :S as seen on en.wikipedia.org/wiki/Riemann_hypothesis#Number_of_zeros Jul 31 comment evaluation of $\operatorname{Arg}\zeta (1/2+is)$ ?? however since $Z(t)$ is real then the argument of $\zeta (1/2+it)$ is just the function $\theta (t)$ but this theta function is just the same as the smooth part of the zeros ¡¡ Jul 28 comment root-finding methods to invert numerically a function OK thanks, we could use a bisection method and then a newton method to imporve the convergence :) Jul 24 comment Eisenstein series solution er sorry about that $z=x+iy$ and $i= \sqrt -1$ Jul 24 comment how to solve an ODE with boundary conditions $y(0)=y(\infty)$ by shooting method another possibility is to make the change of variable $x=uL$ so the new boundary value problem turns into $y(0)=0=y(1)$