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Oct
9
comment inverse function , asymptotics ..
yo mean $ e_{relative}= e_{real}-e_{error}/e_{real} $ and $ e_{absolute}= e_{real}-e_{error} $ ?? thanks for your answer fgp
Oct
8
comment solving this recurrence equation
f(x) is of the order $ f(x)= O(x^{a}) $ at least for big 'x' and an integer positive 'a'
Oct
8
comment What prime number generating algorithms are used?
but shouldn't better to generate primes AT RANDOM ??¿ i mean if i were a 'hacker' i first would study all the prime generating algorithms to crack codes :D :D so perhaps a prime-generating algorithm is not quite safe.
Oct
3
comment inverse function and positivity
you can always DRAW an inverse for any function at least for piecewise continous function, so there is always an inverse
Oct
3
comment inverse function and positivity
thanks Bernhard.. however if we assume $ f(x)=f(-x) $ i think i this case we could always take the positive branch of the function
Sep
24
comment Bessel and cosine function identity formula
OK thaks to oen and Mhenni i messed myself up :D with the power series :D and all the stuff..
Sep
13
comment evaluation of the integral $\int_{0}^{x} \frac{\cos(ut)}{\sqrt{x-t}}dt $
oh sorry i wanted to write 'evaluation' instead of convergence :D ca someone edit the title ?
Sep
13
comment evaluation of the integral $\int_{0}^{x} \frac{\cos(ut)}{\sqrt{x-t}}dt $
aha.. yes Babak nice edit
Aug
27
comment root-finding methods to invert numerically a function
thanks a lot vanna :D
Aug
27
comment Delta function question
$ \delta (-a)=0= \delta (\infty-a) $ and $ f(a)= \infty = g(1/a) $
Aug
8
comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$
anyway thank you all for your answers :D
Aug
8
comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$
shouldn't it be $ \frac{\pi }{2} J_{0}(au/2) $ due to the change of variable $ t \rightarrow t/2 $
Aug
8
comment Evaluating $\int_0^a \frac{\cos(ux)}{\sqrt{a^2-x^2}}\mathrm dx$
aja, thanks what bessel function if possible :) thanks again
Aug
8
comment Riemann Siegel formula modification?
yes intx is integer part (or floor function) of 'x' i did not know how to put it
Jul
31
comment evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ??
umm is there or are there graphics for $ arg\zeta (1/2+it) $ or graphical representaiton of the function $ S(T)= \frac{1}{\pi}arg\zeta (1/2+iT) $ for several values of T , can i see or evaluate the eigenvalue staircase for teh Riemann zeros ??
Jul
31
comment evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ??
but preciselyt this theta functio n $ \theta (t) $ is just the smooth part of the zeros :S as seen on en.wikipedia.org/wiki/Riemann_hypothesis#Number_of_zeros
Jul
31
comment evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ??
however since $ Z(t) $ is real then the argument of $ \zeta (1/2+it) $ is just the function $ \theta (t) $ but this theta function is just the same as the smooth part of the zeros ¡¡
Jul
28
comment root-finding methods to invert numerically a function
OK thanks, we could use a bisection method and then a newton method to imporve the convergence :)
Jul
24
comment Eisenstein series solution
er sorry about that $ z=x+iy $ and $ i= \sqrt -1 $
Jul
24
comment how to solve an ODE with boundary conditions $ y(0)=y(\infty) $ by shooting method
another possibility is to make the change of variable $ x=uL $ so the new boundary value problem turns into $ y(0)=0=y(1) $