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1414
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location Spain , Basque Country , Bilbao
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visits member for 2 years, 9 months
seen Jul 21 at 20:09

i got a degree on Physics and have several ideas on my own , unfortunately i do not have a physics sponsor :) in order to get an investigation grant :)


Jan
26
comment Evaluating $\lim\limits_{x\rightarrow \infty} \frac{f(x)}{x}$ knowing $\lim\limits_{x\to\infty} f(x+1) - f(x)$
for big 'x' $ f(x+1)-f(x) \sim f'(x)$
Jan
23
comment Limit of $\frac{1}{x}\ln{\frac{\exp{x}-1}{x}}$
i have used my calculator and obtained $ 0.49.. $ with $ x=0.0001 $ so the limit must be $ 0.5 $ :D
Jan
21
comment what is the period of this sinusoidal function funtion
we know that $ cos(u+2\pi ) = cos (u) $ for every 'u' so set $ u= \frac{4n \pi}{31}+ \frac{\pi}{5} $
Jan
18
comment evaluation of integral
for big 'x' the integral looks like $ \frac{e^{-2x}}{x} $ so only numerical methods work for this integral , see mathworld.wolfram.com/ExponentialIntegral.html
Jan
17
comment possible value of this series ? either convergent or in the borel sense?
ok thanks :D i didn't know how i cuold not get this solution by myself..
Jan
15
comment “All math is useful eventually”
we can't prove your affirmation even there is physics which eventally will worth nothing is a pity :( for example i can not ge t a job because my math is unesefull :D vixra.org/author/jose_javier_garcia_moreta
Jan
12
comment Why are mathematical proofs that rely on computers controversial?
i think computers does not understand INFINITY am i wrong ? , also unfortunately a numerical proof is not valid otherwise i would have found an operator which yields to Riemann zeros :D :D
Nov
10
comment prime powers and primes
the distance between $ |p^{m}-q| $ with p and q primes could be less than 10 or 100 :) or 1000 see my examples
Oct
31
comment Laplace, Legendre, Fourier, Hankel, Mellin, Hilbert, Borel, Z…: unified treatment of transforms?
in many cases an integral transform $ g(s)=s\int_{0}^{\infty}K(st)f(t) $ can be solved by using the Borel transform, not only for the case $ K(st)=e^{-st} $
Oct
26
comment Given a plot of a function $f(x)$ how to find at which points it is differentiable?
i think you can not.. assume a discontinuity poitn at ceratin value 'a' so for any positive $ \epsilon $ we hve $ f(x+ \epsilon)= 10^{-30000000000000000000000000000000000000000000000000000000000000}+f(x-\epsilo‌​n) $
Oct
15
comment Result of $\sum_{n=1}^{\infty} \frac{\sin(nx)}{n}$
en.wikipedia.org/wiki/Floor_and_ceiling_functions therefore the sum is about $ \frac{\pi}{2}- frac{x}{2\pi} $
Oct
11
comment Laurent series expansion of a function defined by an integral
well perhaps this exists at some other point $ y=1$ or soemthing :)
Oct
11
comment Evaluate $\lfloor \frac{x}{m} \rfloor + \lfloor \frac{x+1}{m} \rfloor + \dots + \lfloor \frac{x+m-1}{m} \rfloor $
this fucntion is periodic $ f(x)=f(x+m) $ so you could try a Fourier series representation for it
Sep
30
comment Solving an inverse spectral problem
then appart from my functions a)-d) what else would i need ? thanks
Sep
30
comment Solving an inverse spectral problem
assume all the spectrum is discrete for example the potential $ V (x) \to \infty $ whenever $ |x| \to \infty$
Sep
19
comment Demystify integration of $\int \frac{1}{x} dx$
you get the expression $ x^{0}$ by direct integration howver if you 'regularize ' this divergence by substraction of the term $ 1/0 $ you get $ \frac{x^{0}-1}{0}=ln(x)$ by expanding the expression by a taylor series
Sep
17
comment Unitary matrices and Riemann zeros is there an error?
but the term $ arg \zeta (1/2+it) $ is also important because you can have thousands of operators with real or imaginary eigenvalues so the mean density of zeros is about $ N(T)= \frac{T}{2\pi}log \frac{T}{2\pi e} $ this does not prove all the zeros are real.
Sep
12
comment Is there a link between divergent series and discontinuities in Fourier integrals?
www3.nd.edu/~lnicolae/Enyart.pdf
Sep
12
comment Scale invariance and the Mellin transform?
only for scale invariant functions $ f(kx)=f(x) $ for the rest this is not true
Sep
12
comment find the minimum of $(a-b)^2+(a-1)^2+(b-1)^2$
a=b=1 is the correct solution and the minimum is 0