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| bio | website | |
|---|---|---|
| location | Spain , Basque Country , Bilbao | |
| age | ||
| visits | member for | 1 year, 7 months |
| seen | 12 mins ago | |
| stats | profile views | 625 |
i got a degree on Physics and have several ideas on my own , unfortunately i do not have a physics sponsor :) in order to get an investigation grant :)
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Apr 15 |
comment |
How important is programming for mathematicians? you can always find a routine with lots of programs or with mathematica or similar you can get your problems numerically solved :D .. anyway if you find interesting watching how algorithm works you could take this course. As a physicist i was ver very bad at programming |
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Apr 15 |
asked | Fourier transform over Lie group |
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Apr 15 |
accepted | meaning of this operator ?? |
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Apr 15 |
asked | meaning of this operator ?? |
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Apr 14 |
comment |
closed form for a series over the Riemann zeta zeros thanks all the people, who answered, of course if i put $ 1/2+iz $ with 'z' complex i can evaluate the sum only over the imaginary parts $ \sum_{n} (is-it_{n})^{-1} $ |
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Apr 14 |
accepted | closed form for a series over the Riemann zeta zeros |
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Apr 14 |
asked | closed form for a series over the Riemann zeta zeros |
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Apr 13 |
answered | Solve $XA + A^T = I$ for $X$ |
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Apr 11 |
asked | Mellin inverse transform |
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Apr 10 |
comment |
solving a PDE in 2 variables without boundary conditions ok , thanks is it possible to get ALL the solutions of $ f(x,y) $ into a closed expression :) |
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Apr 10 |
accepted | solving a PDE in 2 variables without boundary conditions |
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Apr 10 |
asked | solving a PDE in 2 variables without boundary conditions |
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Mar 31 |
comment |
Dilation Invariance for example , if we use the fundamental theorem of arithmetic i guess thati could write $ H(x)= \sum_{m=-\infty}^{\infty}\sum_{p}f(p^{m}) $ so it involves a sum over primes and prime powers |
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Mar 30 |
comment |
Dilation Invariance oK, let us suppose the SUm is ALWAYS convergent and also $f(0)=0$ and $ \int_{0}^{\infty}f(t)dt =0 $ |
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Mar 30 |
asked | Dilation Invariance |
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Mar 29 |
comment |
evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ?? so, i can use with no problem the Riemann-Siegel function to evaluate $ Imlog\zeta (1/2+is) $ on the critical line :) can't i ? |
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Mar 28 |
comment |
evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ?? yes , of course :) perhaps i did not give the expression well |
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Mar 28 |
asked | evaluation of $ \operatorname{Arg}\zeta (1/2+is) $ ?? |
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Mar 21 |
comment |
modular group differential equation solutions 'k' is what physics call the WAVE NUMBER whose square is the energy of the particle in classical and quantum mechanics :) |
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Mar 21 |
asked | modular group differential equation solutions |
