744 reputation
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location Canberra
age
visits member for 2 years, 9 months
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I am a graduate student in pure mathematics at the Australian National University. My primary mathematical interests are in functional analysis, harmonic analysis and microlocal analysis.


Jul
2
awarded  Curious
Apr
15
comment Regularity of Dirichlet Eigenvalues on Lipschitz Domain
At least interior $C^2$ and continuous up to boundary. My problem only has a piecewise smooth boundary though (but the corners are not too bad, so the domain is still Lipschitz).
Apr
15
comment Regularity of Dirichlet Eigenvalues on Lipschitz Domain
Thanks for the reference, this book should be quite useful in general. It seems the Dirichlet regularity result in this section assumes at least a $\mathcal{C}^2$ boundary though.
Apr
15
asked Regularity of Dirichlet Eigenvalues on Lipschitz Domain
Feb
18
comment show that $f$ is not integrable on $[0,1]$
It is equal to cos a.e., not sin. And it is discontinuous at every point in the interval, not just the rationals. ie it is not Riemann integrable.
Feb
18
comment What is wrong with this equations?
(5-5) and (x-y) are both zero.
Feb
10
answered Showing that the square root is monotone
Jan
7
comment How to prove the inequality: $\frac{(1+x)^2}{2x^2+(1-x)^2}+\frac{(1+y)^2}{2y^2+(1-y)^2}+\frac{(1+z)^2}{2z^2+(1-z)^2}\leq 8$
Thanks. Out of interest, where did the motivation for looking at: $(4a+1)(a-1/3)^2$ come from?
Jan
7
accepted How to prove the inequality: $\frac{(1+x)^2}{2x^2+(1-x)^2}+\frac{(1+y)^2}{2y^2+(1-y)^2}+\frac{(1+z)^2}{2z^2+(1-z)^2}\leq 8$
Jan
7
revised How to prove the inequality: $\frac{(1+x)^2}{2x^2+(1-x)^2}+\frac{(1+y)^2}{2y^2+(1-y)^2}+\frac{(1+z)^2}{2z^2+(1-z)^2}\leq 8$
edited body; edited title
Jan
7
asked How to prove the inequality: $\frac{(1+x)^2}{2x^2+(1-x)^2}+\frac{(1+y)^2}{2y^2+(1-y)^2}+\frac{(1+z)^2}{2z^2+(1-z)^2}\leq 8$
Nov
28
revised restriction of functions of several variables
added 1 characters in body
Nov
28
comment Definition of a tangent space
Differentiability has a natural implicit definition on smooth manifolds: en.wikipedia.org/wiki/…. No embedding in Euclidean space is involved in this definition.
Nov
28
answered restriction of functions of several variables
Oct
9
awarded  Yearling
Sep
12
answered The Idea Behind Taylor Series
Aug
2
accepted $O_{\mathcal{S}'\rightarrow \mathcal{S}}(h^\infty)$
Aug
2
comment $O_{\mathcal{S}'\rightarrow \mathcal{S}}(h^\infty)$
Okay thankyou, I wasn't sure if it was a pointwise bound or something more uniform. Perhaps a generalisation of the UBP to locally convex vector spaces makes this distinction moot anyway.
Aug
2
comment $O_{\mathcal{S}'\rightarrow \mathcal{S}}(h^\infty)$
Yes, this is how I interpret such notation when the domain and codomain are normed spaces, but this is not the case here...how can we assert the existence of an operator norm? @RGB $O(h^\infty)$ means $O(h^n)$ for all positive integers $n$ as $h$ gets small.
Aug
1
asked $O_{\mathcal{S}'\rightarrow \mathcal{S}}(h^\infty)$