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Oct
17
asked I have a recursively defined function, and another function involving powers of a matrix. How can I show that they are equal?
Oct
8
comment Given $f(x)$ its inverse function, domain and range
@Assad well, an inverse function does not always exist. But where one does, yes it holds true.
Oct
8
answered If a linear system has no free variables, then it is consistent: Why is the statement false?
Oct
8
answered Given $f(x)$ its inverse function, domain and range
Oct
8
answered How do I proove the symmetry of Metric space?
Oct
8
asked Prove that flow is a linear combination of flow cycles and flow paths
Oct
7
comment Calculus remark I forgot.
You're going to need to put some more restrictions on $X$. For instance, this clearly doesn't hold for the empty set. Or the set of all integers. Or the set of negative real numbers. Or $[0,1] \backslash \{x:x=1/n,n\in\mathbb{N}\}$. Etc. But there's something there if you refine it a little bit.
Oct
5
awarded  Yearling
Oct
5
accepted Help with a step in Diestel's proof of Tutte's theorem in Graph Theory
Oct
5
asked Help with a step in Diestel's proof of Tutte's theorem in Graph Theory
Sep
29
accepted If $X\sim \exp(\lambda)$ and $Y\sim \exp(\mu)$ then $P(X\leq Y)=\frac{\lambda}{\lambda+\mu}$. Is there an intuitive interpretation for this fact?
Sep
29
comment If $X\sim \exp(\lambda)$ and $Y\sim \exp(\mu)$ then $P(X\leq Y)=\frac{\lambda}{\lambda+\mu}$. Is there an intuitive interpretation for this fact?
@Did that's a fantastic way to put it. If you made this an answer I would accept it.
Sep
19
asked If $X\sim \exp(\lambda)$ and $Y\sim \exp(\mu)$ then $P(X\leq Y)=\frac{\lambda}{\lambda+\mu}$. Is there an intuitive interpretation for this fact?
Sep
15
revised Intro to proofs in real analysis 3
translated notation to latex
Sep
15
suggested approved edit on Intro to proofs in real analysis 3
Sep
10
comment Is it a vector space?
@realmatrix note, "it is the equation of a line" is not sufficient to show that it is a vector space. $y=x+1$ is the equation of a line, but the points satisfying that equation do not form a vector space.
Sep
4
answered What does the sentence “The only sub-algebras of $\mathbb{R}^{2}$ are $0,\mathbb{R}^{2},\mathbb{R}(0,1),\mathbb{R}(1,0),\mathbb{R}(1,1)$” mean?
Aug
2
accepted Does the probability distribution associated with this pdf have a name?
Aug
2
comment Does the probability distribution associated with this pdf have a name?
beautiful, thank you so much!
Aug
2
asked Does the probability distribution associated with this pdf have a name?