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seen Dec 16 at 6:38

Dec
15
accepted How can I recursively approximate a moving average and standard deviation?
Dec
11
revised How can I recursively approximate a moving average and standard deviation?
added 10 characters in body
Dec
11
asked How can I recursively approximate a moving average and standard deviation?
Nov
25
asked Are these two definitions of the natural numbers equivalent?
Oct
23
awarded  Notable Question
Oct
21
awarded  Popular Question
Oct
5
awarded  Yearling
Sep
12
awarded  Popular Question
Aug
10
awarded  Popular Question
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jun
26
asked Sampling from a graph
Jun
26
revised how to solve $\sqrt{x^2 -2x} -x =0$?
changed to latex
Jun
18
comment Contraposition and law of excluded middle
@Materialist as far as I know (I am not an expert), the law of the excluded middle is formally equivalent to negation elimination. If we can obtain a statement without using negation elimination (i.e. without invoking $\neg\neg P \iff P$), we have proven it without making use of the law of the excluded middle. Here, we begin with, say, $(A\to B) \& \neg B$. If we can now show $\neg A$, then we've shown that $(A\to B)\to (B\to A)$. Now, assume $A$; we show that this leads to $B\&\neg B$, which allows us to conclude $\neg A$ without making use of the law of the excluded middle.
Jun
18
revised Relationship between Binomial and Bernoulli?
edited tags
Jun
18
answered Relationship between Binomial and Bernoulli?
Jun
18
answered Contraposition and law of excluded middle
Jun
18
comment Extended Monte Hall problem (Hallway)
We start with $n$ doors, and each door has $n$ doors behind it? The answer will be the same—you're not really changing the problem very much; you're just jiggling some parameters around a little bit. Now not switching wins when you select the right door and then select the right door, which happens with probability $1/n^2$. Switching wins when you select the wrong door, change to the right door, and then select the right second door, which happens with probability $\frac{(n-1)}{n}\times\frac{1}{n-1}\times\frac{1}{n}>1/n^2$. Have I interpreted your question correctly?
Jun
12
awarded  Announcer
Jun
6
revised On prime(less)ness and composite(less)ness of 1
added 542 characters in body