| bio | website | andresbotero.co |
|---|---|---|
| location | Colombia | |
| age | 27 | |
| visits | member for | 1 year, 7 months |
| seen | Dec 24 '12 at 2:38 | |
| stats | profile views | 5 |
|
Sep 30 |
awarded | Scholar |
|
Sep 30 |
accepted | Trigonometric identity proof |
|
Sep 30 |
comment |
Trigonometric identity proof Nice, keeping-it simple approach (plus the addition in the edit). I will choose Srivatsan Narayanan answer mostly because he took off from there I left. In any case, thank you very much! PS: I’m reading your other answer, and some linked in that question. |
|
Sep 30 |
comment |
Trigonometric identity proof Yes, but I didn’t think of that approach. How would have been? cos(A + 0)? (Trying it right now) |
|
Sep 30 |
comment |
Trigonometric identity proof Excellent question! No, I did not have the half-angle formulas. Many answers already, but I didn’t mention anything of half-angle because I didn’t even know about them until now. |
|
Sep 30 |
comment |
Trigonometric identity proof Yes, I solved it using the 1 - 2sin^2x variant, but I would really appreciate if you could please explain the above inquiry before checking this topic. Oh, by the way: thank you! |
|
Sep 30 |
awarded | Student |
|
Sep 30 |
comment |
Trigonometric identity proof @Srivatsan I mean, why the double angle formulas? Simply because they could work? Sorry, perhaps I’m overcomplicating, but I’m trying to understand the background of that decision. |
|
Sep 30 |
comment |
Trigonometric identity proof Wait a minute, why 2x now? I mean, why the double angle now? How did you come to the conclusion that you should use those formulas in order to solve the problem? I mean, besides “experience”. |
|
Sep 30 |
asked | Trigonometric identity proof |