Andrés Botero
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 Sep 30 awarded Scholar Sep 30 accepted Trigonometric identity proof Sep 30 comment Trigonometric identity proof Nice, keeping-it simple approach (plus the addition in the edit). I will choose Srivatsan Narayanan answer mostly because he took off from there I left. In any case, thank you very much! PS: I’m reading your other answer, and some linked in that question. Sep 30 comment Trigonometric identity proof Yes, but I didn’t think of that approach. How would have been? cos(A + 0)? (Trying it right now) Sep 30 comment Trigonometric identity proof Excellent question! No, I did not have the half-angle formulas. Many answers already, but I didn’t mention anything of half-angle because I didn’t even know about them until now. Sep 30 comment Trigonometric identity proof Yes, I solved it using the 1 - 2sin^2x variant, but I would really appreciate if you could please explain the above inquiry before checking this topic. Oh, by the way: thank you! Sep 30 awarded Student Sep 30 comment Trigonometric identity proof @Srivatsan I mean, why the double angle formulas? Simply because they could work? Sorry, perhaps I’m overcomplicating, but I’m trying to understand the background of that decision. Sep 30 comment Trigonometric identity proof Wait a minute, why 2x now? I mean, why the double angle now? How did you come to the conclusion that you should use those formulas in order to solve the problem? I mean, besides “experience”. Sep 30 asked Trigonometric identity proof