Kyle Schlitt

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bio website location age 30 member for 3 years, 2 months seen Dec 17 at 19:58 profile views 547

I am a PhD student at University of Alberta.

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 Dec17 accepted A Pasting lemma for measurable functions Nov22 awarded Popular Question Nov17 awarded Popular Question Nov16 revised Questions about Listening To Presented Material edited title Nov15 answered Finitely representable space Nov15 comment Finitely representable space OK. I see the argument. I almost want to delete the question now. Thanks for any attention that has been given to this. Nov15 comment Finitely representable space I had an idea, but haven't checked it yet. Just start with a countable dense subset and throw away the ones you dont need for linear independance. Nov15 comment Finitely representable space Thanks, suppose further that $F$ is separable. I cleaned up my question which was sloppy, sorry! Nov15 revised Finitely representable space added 15 characters in body Nov15 asked Finitely representable space Sep30 awarded Explainer Sep30 awarded Yearling Sep24 awarded Autobiographer Sep19 revised Integration over subsets of the complex plane. $t$ and $\theta$ were being used for the same variable Sep19 comment Integration over subsets of the complex plane. I'm a bit embarassed I didn't make this connection. We do this all the time for continuous functions $f:\mathbb{R}^{2}\to\mathbb{R}$. Thanks for the help! Sep19 accepted Integration over subsets of the complex plane. Sep19 asked Integration over subsets of the complex plane. Aug9 comment Neighborhood Base (the definition) While I agree with you in other contexts, this is not really what the question was about. It does not follow at all from the definition I provided that the neighbourhoods should contain $x$. Arturo Magidin's comments above have answered the question. Jul13 accepted Convolution of $L^1(G)$ functions with elements of $M(G)$. Jul13 comment Convolution of $L^1(G)$ functions with elements of $M(G)$. Thanks very much!