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 Nov26 awarded Popular Question Sep24 awarded Autobiographer Jul2 awarded Curious Nov2 comment Prove that if $a$ and $b$ are odd, coprime numbers, then $\gcd(2^a +1, 2^b +1) = 3$ Thanks, I think I will see where I can get with this. Nov2 comment Prove that if $a$ and $b$ are odd, coprime numbers, then $\gcd(2^a +1, 2^b +1) = 3$ Good point, I was thinking of that at first, but your right, it doesn't prove that gcd is 3 Nov2 revised Prove that if $a$ and $b$ are odd, coprime numbers, then $\gcd(2^a +1, 2^b +1) = 3$ added 84 characters in body Nov2 asked Prove that if $a$ and $b$ are odd, coprime numbers, then $\gcd(2^a +1, 2^b +1) = 3$ Oct18 comment How many ordered pairs of positive integers @Andre: $\frac{1}{a} + \frac{1}{b} = \frac{1}{p}$ Oct18 asked How many ordered pairs of positive integers Oct17 awarded Teacher Oct17 answered A request for a suggestion for a mathematics talk aimed at first year and second year undergraduate students in science Oct6 comment Combinatorial proof help Wow, thanks for pointing me to a geometry proof. Very interesting :D Oct6 accepted Combinatorial proof help Oct6 comment Combinatorial proof help But we have to prove it using double counting. But yes, an algebraic proof would look nice and neat. Oct6 comment Combinatorial proof help Thanks for your help :) I finished the proof a while ago, I forgot to close the question. Oct5 accepted Lattice Paths Question Oct5 awarded Scholar Oct5 accepted $16$ natural numbers from $0$ to $9$, and square numbers: how to use the pigeonhole principle? Oct5 comment $16$ natural numbers from $0$ to $9$, and square numbers: how to use the pigeonhole principle? Oh, okay now I think I got it. So when two products are in the same hole, the powers of this final product are all even. Hence it proves that there is always a product which forms even powers. Oct5 comment Lattice Paths Question @Ross: no, (0, 1) and (1, 0) are not allowed. We can only jump in steps of (1, n)