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seen Mar 21 '13 at 7:18

Sep
28
awarded  Popular Question
Jul
2
awarded  Curious
Mar
21
comment rational fractions and the negative sign
That's a good point. 1 vote up.
Mar
21
accepted rational fractions and the negative sign
Mar
21
comment rational fractions and the negative sign
Thanks. It is easier to view things when we indeed start from the cross-multiplied form of the expression as you did. 1 vote up.
Mar
21
revised rational fractions and the negative sign
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Mar
21
asked rational fractions and the negative sign
Nov
9
accepted physical meaning of the vector $(A \cdot \nabla) A$
Nov
8
comment physical meaning of the vector $(A \cdot \nabla) A$
@ Berci I really don't know. If only 1 field component $H_z$ exists and for $(A \cdot \nabla) A$ to be $0$, then $\frac{\partial A_z}{\partial z}$ should be zero. Is this right to think this way? 1 vote up
Nov
8
comment physical meaning of the vector $(A \cdot \nabla) A$
@ Harald Hanche-Olsen. Can we say that $(A \cdot \nabla) A \neq 0$ if we have the field effects in more than one direction? My post showed that having only one component $H_z$ in that case leads to $(A \cdot \nabla) A = 0$.
Nov
8
comment physical meaning of the vector $(A \cdot \nabla) A$
@ Harald Hanche-Olsen . Thanks. If my $A$ is a magnetic field vector such as the magnetic field intensity $H$, then your answer implies that there is no curvature in the field lines. 1 vote up.
Nov
8
asked physical meaning of the vector $(A \cdot \nabla) A$
Mar
17
comment Is there a good way to compute Christoffel Symbols
@Thomas Rot Thanks for the link. 1 vote up.
Mar
15
comment Is there a good way to compute Christoffel Symbols
@Thomas Rot Which mathematica packages are good for the computation of Christoffel symbols? Thanks
Mar
8
comment Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?
@zhen Lin Yes not explicitly perhaps when just looking at the equation of motion but we are definitely using the spatial coordinates derivatives to arrive at the new equation of motion.
Mar
8
comment Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?
@Zhen Lin Thanks. I have updated my post. As you can see we have differentiation with respect to the spatial coordinates. 1 vote up.
Mar
8
revised Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?
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Mar
8
revised Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?
added 76 characters in body
Mar
8
revised Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?
added 135 characters in body
Mar
8
asked Conversion of motion equation from Cartesian to Polar coordinates: Is covariant differentiation necessary?