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Apr
15
answered How to visualize a line integral
Apr
15
revised How to visualize a line integral
added 23 characters in body
Apr
15
answered If we have n variables and we assign arbitrary values to all but one of them, can we always find a solution to the equation?
Apr
15
answered For $\mathbb{Q[x]}/ I \cong$ $\mathbb{Q}$, proving kernel
Apr
14
comment Base 12 Versus Base 16
I made no such claim. See my first sentence.
Apr
14
answered Book recommendation for Abstract Algebra
Apr
14
comment Symmetric Group and Alternating Subgroup
Any index 2 subgroup is normal. Why? Let $H$ have index 2 in $G$. Then its left cosets are $H$ and everything left over (i.e. $G-H$ the set complement of $H$ in $G$). Now the right cosets must be $H$ and again everything that is left-over: $G-H$. Therefore, the left and right cosets match (i.e. $H$ is normal). The key is that when $H$ has index 2, there isn't any room for the left/right cosets to be mismatched. :)
Apr
14
revised Prove that the set $[0,1)$ is a closed set in the half-open interval topology of $\mathbb{R}$.
edited title
Apr
14
answered Prove that the set $[0,1)$ is a closed set in the half-open interval topology of $\mathbb{R}$.
Apr
14
comment Prove that the set $[0,1)$ is a closed set in the half-open interval topology of $\mathbb{R}$.
I think you mean "Prove that the set $[0,1)$ is a closed set in the half-open interval topology of $\mathbb{R}$"
Apr
14
revised Symmetric Group and Alternating Subgroup
added 978 characters in body
Apr
14
answered Symmetric Group and Alternating Subgroup
Apr
14
answered finding eigenvalues and eigenspaces of a linear operator
Apr
14
comment Base 12 Versus Base 16
@Neil I'm not quite sure what your comment is addressing. In base 10, you can see divisibility by 10's, 5's, and 2's. This is no misconception. This is fact. And, yes, it is because of the base 10 "encoding" we've chosen for our numbers. What you've said about base 12, is mentioned in my original post (here you can "see" divisibility by 12's, 6's, 4's, 3's and 2's).
Apr
14
comment Is $\exp(x)$ the same as $e^x$?
@Carl Mummert Interesting. I definitely haven't noticed authors using such a distinction, but it actually quite a reasonable one. Thanks! :)
Apr
12
awarded  Nice Answer
Apr
10
comment Is $\exp(x)$ the same as $e^x$?
@Carl Mummert How so? I can't think of a time when $\exp(x)$ and $e^x$ were defined differently. In every case I can think of this is just variant notation (much like $\sin^{-1}(x)$ vs. $\mathrm{arcsin}(x)$).
Apr
9
awarded  Guru
Apr
9
awarded  Good Answer
Apr
9
awarded  Enlightened