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Sep
30
awarded  Explainer
Sep
29
comment Decimal binary sequences that cannot be greater than $1$
So, for example, it's $$.(0)(1)(2)\cdots(98)(99)\ \to \ .(0)(1)(2)\cdots(98+98/2)(1)$$ and not $$.012\cdots9899 \ \to \ .012\cdots98(9+ 8/2)1\ ??$$
Sep
28
revised Determine the $n$th string among those of a given length in alphabetical order starting at a given string and using a given character set?
Clarify the presumed meaning; add relevant tags.
Sep
28
suggested approved edit on Determine the $n$th string among those of a given length in alphabetical order starting at a given string and using a given character set?
Sep
27
revised Determine the $n$th string among those of a given length in alphabetical order starting at a given string and using a given character set?
added 199 characters in body
Sep
27
answered Determine the $n$th string among those of a given length in alphabetical order starting at a given string and using a given character set?
Sep
26
revised Prove there exist a $p$ so that the inequality holds
fix typos
Sep
26
revised Prove there exist a $p$ so that the inequality holds
fix typo
Sep
26
answered Prove there exist a $p$ so that the inequality holds
Sep
24
awarded  Autobiographer
Sep
20
awarded  Yearling
Sep
17
comment Combining large number of independent probabilities
Cross-posted.
Sep
17
comment Help applying Bayes' Law
You're welcome. Note: this solution assumes that instead of "76% of the time we do not need to go to m3, we found it in m2", you really meant "76% of the time we do not need to go to m3, we found it in m2 or in m1". Since this answer has been accepted, I presume that it's the value given by your problem-source.
Sep
17
comment Help applying Bayes' Law
I'm assuming that instead of "76% of the time we do not need to go to m3, we found it in m2", you really meant "76% of the time we do not need to go to m3, we found it in m2 or in m1". Also, what does the problem-source say is the correct answer?
Sep
17
answered Help applying Bayes' Law
Sep
16
comment What does it really mean when we say that the probability of something is zero?
@krb686 - "How so?": The computable reals in any interval form a null set (i.e., whose Lebesgue measure is zero). This is a mathematical issue, not a physical one.
Sep
16
comment Finding an expression for a joint probability if two random variables have the same distribution function.
@MathDamon - I've added that to the answer.
Sep
16
revised Finding an expression for a joint probability if two random variables have the same distribution function.
add similar development for min(X,Y)
Sep
15
comment What does it really mean when we say that the probability of something is zero?
Indeed, if X has a continuous distribution on a real interval then ℙ( "X is computable")=0.
Sep
15
comment What does it really mean when we say that the probability of something is zero?
Or you can think like the Queen: "Alice laughed: "There's no use trying," she said; "one can't believe impossible things." "I daresay you haven't had much practice," said the Queen. "When I was younger, I always did it for half an hour a day. Why, sometimes I've believed as many as six impossible things before breakfast." $\sim$ Alice in Wonderland