5,587 reputation
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bio website sites.google.com/site/liduzg
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visits member for 3 years, 1 month
seen Oct 17 at 15:11

My real name is LI Du.

Ma Ming is my long-time pseudonym on the Internet.

I am a maths PhD student in University of Göttingen.


Sep
30
awarded  Explainer
Sep
29
reviewed Approve suggested edit on Tangential and normal components of acceleration acting on a dropped bomb
Sep
24
awarded  Autobiographer
Sep
19
awarded  Yearling
Sep
5
revised Show that $\sqrt[3]{2+\frac {10} 9\sqrt 3}+\sqrt[3]{2-\frac {10} 9\sqrt 3}=2$
deleted 136 characters in body
Sep
1
revised Decide whether the following series converges $\sum_{n=1}^{\infty}\dfrac{(\ln n)^2}{n^{3/2}}$
added 2 characters in body
Sep
1
answered Decide whether the following series converges $\sum_{n=1}^{\infty}\dfrac{(\ln n)^2}{n^{3/2}}$
Aug
19
reviewed Approve suggested edit on Integrating $\int \sin^n{x} \ dx$
Aug
18
comment Is there a name for this point?
@curious just add the adjective "weight" to whatever name you prefer.
Aug
18
answered Is there a name for this point?
Aug
18
revised Minimize $\cos(t)\cos(t-\alpha)$
deleted 3 characters in body
Aug
17
reviewed Approve suggested edit on Minimize $\cos(t)\cos(t-\alpha)$
Aug
17
answered Minimize $\cos(t)\cos(t-\alpha)$
Aug
17
answered Prove limit of function
Aug
17
revised Maximum area of quadrilateral with sides and diagonals not exceeding a given value
deleted 10 characters in body
Aug
17
revised Maximum area of quadrilateral with sides and diagonals not exceeding a given value
deleted 2 characters in body
Aug
17
comment Maximum area of quadrilateral with sides and diagonals not exceeding a given value
@IkramIbrahim The area of the quadrilateral, either convex or concave, is exactly $\frac{lm\sin \alpha}{2}$. see en.wikipedia.org/wiki/…
Aug
15
revised Summation of general series
added 39 characters in body
Aug
15
answered Summation of general series
Aug
15
comment Maximum area of quadrilateral with sides and diagonals not exceeding a given value
It the answer solves your homework, please consider click the accept bottom.