meta user
network profile
| bio | website | |
|---|---|---|
| location | United States | |
| age | 24 | |
| visits | member for | 1 year, 8 months |
| seen | yesterday | |
| stats | profile views | 10 |
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Jan 9 |
accepted | Average proportion for proportions with different denominators |
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Jan 9 |
accepted | Limit of $1/x^2$ - Apostol 3.2, Example 4 |
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Oct 29 |
awarded | Tumbleweed |
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Oct 22 |
asked | Average proportion for proportions with different denominators |
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Apr 23 |
awarded | Scholar |
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Apr 23 |
accepted | Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ |
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Feb 15 |
comment |
Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ @BrianM.Scott Yeah, sorry. I looked through and I couldn't find it, but once gingerjin gave a proof I recognized it. I was too impatient, is all. Thanks anyways! |
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Feb 15 |
comment |
Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ Thank you. This is a really clear explanation! |
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Feb 15 |
comment |
Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ @JonasMeyer I'll see if I can find something about $e^u$. Maybe that will help me understand this. |
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Feb 15 |
comment |
Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ @HenningMakholm Apostol's "One Variable Calculus". If there is a proof, I'm missing it. |
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Feb 15 |
revised |
Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ edited body |
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Feb 15 |
asked | Proof that $\int_1^x \frac{1}{t} dt$ is $\ln(x)$ |
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Nov 29 |
comment |
Limit of $1/x^2$ - Apostol 3.2, Example 4 Oh! I think I get it. Any neighborhood N(0) will contain points such that 0<x<{1\over A+2}, and for those points f(x) > A+2. You can't get around that, no matter what δ you choose. What makes me sure that I get it is that now I don't understand why I didn't see that in the first place. |
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Nov 29 |
comment |
Limit of $1/x^2$ - Apostol 3.2, Example 4 On reflection, I'm not sure either. This is helping, though. Thanks! |
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Nov 29 |
comment |
Limit of $1/x^2$ - Apostol 3.2, Example 4 Thanks for the formatting. I briefly tried to get it into LaTex, but I gave up after nothing worked. Haha. I've tried to ask questions where I didn't explain as much, and the person I was asking either refused to help or started talking about a part of the problem that I wasn't asking about. In this case, I had already burned through all of my mathy friends, but they are all at least two years out from real analysis, and couldn't help very much. They did help me get this far, though. |
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Nov 29 |
comment |
Limit of $1/x^2$ - Apostol 3.2, Example 4 I think I get it. Is this like saying that for a given δ1 such that for 0 < x < δ1, if δ1 does not work, than no δ > δ1 will work? |
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Nov 29 |
awarded | Student |
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Nov 29 |
asked | Limit of $1/x^2$ - Apostol 3.2, Example 4 |
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Oct 9 |
awarded | Supporter |
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Sep 29 |
answered | Determining the truth value of a statement |
