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May
6
comment If I know $AB$, how can I calculate $BA$?
Easier question, some ideas for a general answer: math.stackexchange.com/q/731349/16192
May
6
comment If I know $AB$, how can I calculate $BA$?
@José you will have 12 variables and 9 constraints for the system of equations
May
6
comment Sigma algebra generated by a quadratic function
I vaguely recall it is sufficient to represent all open intervals.
Apr
29
comment Biased Asymmetric Random Walk
not clear you can reuse the same result. This walk is biased, so larger p means you will have drift; also skipping one may be a problem -- i.e. you can reach -1, and then skip over to 1 if $n<0$.
Apr
29
comment $\int_{-1}^1 \int_{-1}^1 \sqrt{\frac{1+x-y-xy}{1-x+y-xy}} \, dx\,dy $
This is equivalent to $$\iint_{[-1,1]^2} \sqrt{\frac{(1+x)(1-y)}{(1-x)(1+y)}} dxdy$$, and the latter integral clearly has issues at $x=1$ and $y=-1$ -- are you sure it exists?
Apr
28
comment Minimize the norm of $w$.
@user235204 thanks fixed
Apr
28
comment Using equation of a line to find infinitely many different solutions of $ x^2 - 2y^2 = 1$
I don't understand. How do you know that you will get infinitely many integer solutions?
Apr
28
comment Solving Integral that includes radical expression 2
@Zach466920 i am not arguing -- just posting here for intuition builder
Apr
28
comment Solving Integral that includes radical expression 2
wolframalpha.com/input/?i=integrate+sqrt%7Bt%5E4-c%7D+dt
Apr
28
comment Prove that $371\cdots 1$ is not prime.
I wonder why the downvote...
Apr
22
comment Curve that lies on a solution surface
@user this is beyond me at this point
Apr
22
comment Curve that lies on a solution surface
@user for example, the surface where $f(x,y,u) = \sqrt{2}$ would certainly be a constant but non-zero $f$
Apr
22
comment Curve that lies on a solution surface
@user i think "$f$ is constant" and $f=0$ are not the same, but latter is special case of the former
Apr
22
comment Curve that lies on a solution surface
@user likely because you want to claim something about all curves in the solution surface with some nice properties
Apr
22
comment Finding upper bounds of a set
Yes, it is correct.
Apr
22
comment Curve that lies on a solution surface
@user if you like, this can be said.
Apr
22
comment Recurrence Relations with Geometric Series
@MD_90 not so simple. Notice that $5^{k-1} >> 2^k$ even though the exponent is smaller since $2^k = 2 \cdot 2^{k-1}$...
Apr
1
comment Is this statement correct $f(n) = \theta(n) \land g(n) = \Omega(n) \Longrightarrow f(n)g(n) = \Omega(n^2)$?
@Rinzler yes indeed
Mar
18
comment How do I solve this equation when x approaches zero?
Do you know Taylor series or L"Hospital's Rule? Both would work here...
Mar
9
comment Solve the Lagrangian dual problem
@e2l3n I don't think so, but it's been a while since i looked at these