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Jun
11
comment converting asymptotic little-oh into big-oh
If $f(n) \cdot n^{1/4-\epsilon} \to 0$ then $f(n) = O(n^{-1/4})$, not $O(n^{1/4})$ as you have claimed
Jun
11
comment How many arithmetic operations are required to do this polynomial division?
depnds on the degree of $p$?
Jun
11
comment converting asymptotic little-oh into big-oh
in std notation, $f(n) = O(n^{-1/4})$
Jun
11
answered Solving this Inequation
Jun
11
comment Probability of not choosing from a lot
that's not what it says in the question -- "10 out of every 1000 are defective" but i can see how you want to interpret it like that. i wasn't the one who downvoted btw
Jun
11
comment Probability of not choosing from a lot
@BelginFish see the update...
Jun
11
revised Probability of not choosing from a lot
added 323 characters in body
Jun
11
comment Probability of not choosing from a lot
this is wrong. when you've picked the first one, the odds for the second one change
Jun
11
answered Probability of not choosing from a lot
Jun
11
comment Probability of not choosing from a lot
Please add your own thoughts on the problem. People here don't usually like to do your hw for you
Jun
11
answered Closed Form Solution for Minimization involving Standard Normal CDF and PDF
Jun
11
comment Find $\lim\limits_{x\to \infty} \frac{x\sin x}{1+x^2}$
@JesterTran yes. Exactly
Jun
11
comment Find $\lim\limits_{x\to \infty} \frac{x\sin x}{1+x^2}$
@JesterTran LHospital cannot be used when limits don't exist. You need too make s bonding argument like shown in other answers
Jun
11
comment Find $\lim\limits_{x\to \infty} \frac{x\sin x}{1+x^2}$
@JesterTran it is neither $+\infty$ or $-\infty$, it does not exist...
Jun
11
comment Find limit of the quotient
This doesn't quite work -- note that in your case you have $-\infty$ instead of $N$. What is the definition of such a limit?
Jun
11
revised Find limit of the quotient
added 175 characters in body; edited title
Jun
10
answered Find $\lim\limits_{x\to \infty} \frac{x\sin x}{1+x^2}$
Jun
10
revised Connection between $\epsilon-\delta$ definition of limit and Weierstrass definition of continuous functions
added 1 character in body
Jun
10
comment What's wrong with this?
@Thomas i suppose he is trying to argue that $e^x = 1$ implies $x=0$, which is obviously problematic in complex arithmetic. Not sure what he needs the logs for.
Jun
10
comment Prove $\lim\limits_{n\to\infty}\frac{1}{\sqrt[n]{n!}}=0$
it is right, not sure of other approaches