8,078 reputation
825
bio website linkedin.com/in/gt6989b
location New York, NY
age 36
visits member for 3 years, 4 months
seen 2 days ago

Dec
8
answered How can I rotate a point 45 degrees counterclockwise around any point?
Dec
8
answered Finding Transformation inverse
Dec
8
awarded  Caucus
Dec
8
answered random variables (X,Y) have the following joint PDF
Dec
8
revised random variables (X,Y) have the following joint PDF
LaTeX
Dec
8
comment optimization with non smooth constraint
@JesseRJ MATLAB is not a good solver. Maybe CVXOPT? abel.ee.ucla.edu/cvxopt/examples/index.html There are others that are free. The best paid one is CPLEX sold by IBM
Dec
8
comment optimization with non smooth constraint
@JesseRJ Modern optimizers have a special type for that constraint.
Dec
8
comment optimization with non smooth constraint
@JesseRJ are you using linear optimization only, or can you have binary variables?
Dec
8
comment optimization with non smooth constraint
@JesseRJ I don't understand your comment, likely a part got deleted by accident?
Dec
8
answered express vector with other vectors
Dec
8
answered optimization with non smooth constraint
Dec
8
comment Find $\lim_{x \to -8} \frac{\sqrt{1 - x} - 3 }{ 2 + \sqrt[3] {x}}$
@omidh Please see the update, can you finish it now? Feel free to accept the solution when you understand it to the end...
Dec
8
revised Find $\lim_{x \to -8} \frac{\sqrt{1 - x} - 3 }{ 2 + \sqrt[3] {x}}$
added 454 characters in body
Dec
5
answered expected value - two etaps
Dec
5
comment expected value - two etaps
Likely, etaps means stages and eagle means tail.
Dec
5
answered Find $\lim_{x \to -8} \frac{\sqrt{1 - x} - 3 }{ 2 + \sqrt[3] {x}}$
Dec
5
comment Find $\lim_{x \to -8} \frac{\sqrt{1 - x} - 3 }{ 2 + \sqrt[3] {x}}$
Do you know derivatives? can you use L'Hospital's rule?
Dec
5
revised Riccati differential equation
added 2 characters in body
Dec
5
comment Find $\lim_{x \to -8} \frac{\sqrt{1 - x} - 3 }{ 2 + \sqrt[3] {x}}$
PLease exhibit your work on the problem and we will be glad to give some hints. How about expanding the root in the numerator into Taylor series around $x=1$?
Dec
5
answered Word Permutations