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Jun
16
revised Problem with Solve a Differential Equation
added 31 characters in body
Jun
16
comment Normal distribution for bags of coal produced from a machine.
@Julian notice this matches the answer given in (i). Can you take care of (ii)?
Jun
16
answered Get Rank from two Ranks
Jun
16
comment Get Rank from two Ranks
Yes. Writing the solution for you.
Jun
16
comment Normal distribution for bags of coal produced from a machine.
@Julian you just copied over your claim from the original question, it will not fit for the solution method i am proposing. What is $\mathbb{P}[X > 56] \times \mathbb{P}[Y > 56]$??
Jun
16
comment Get Rank from two Ranks
Can you please elaborate on how you determine the first and the second rank exactly, and how would you like to combine them?
Jun
16
comment Probability of multiple dice rolls with decreasing amounts of dice
maybe a specific example would help. I am familiar with Risk but not Axis and Allies...
Jun
16
comment Get Rank from two Ranks
What does this mean -- "first rank" and "second rank"?
Jun
16
answered Solution to Fibonacci Recursion Equations
Jun
16
comment How to find number which is greater?
@Winther thank you, fixed
Jun
16
revised How to find number which is greater?
edited body
Jun
16
comment How to find number which is greater?
@Bhaskara-III see update
Jun
16
revised How to find number which is greater?
added 294 characters in body
Jun
16
comment How to find number which is greater?
@Bhaskara-III do you know calculus -- derivatives?
Jun
16
answered How to find number which is greater?
Jun
16
comment Interpolation between 2 points on the perimeter of a circle?
if the problem is with the use of $\sin$ and $\cos$, you can approximate them using 3-4 terms in the Taylor series
Jun
16
comment Interpolation between 2 points on the perimeter of a circle?
What does it mean "without use of angles"? Parameterize your curve as $x(t) = \cos (t\pi/2), y(t) = \sin (t\pi/2)$ with $0 \le t \le 1$ then $t=1/2$ comes out to $x = y = \sqrt{2}/2$
Jun
16
comment Prove that $2^{mn}$ is always greater than or equal to $m^n$
@coffeemath yes
Jun
16
revised Prove that $2^{mn}$ is always greater than or equal to $m^n$
added 1 character in body
Jun
16
answered Prove that $2^{mn}$ is always greater than or equal to $m^n$