Reputation
8,964
Top tag
Next privilege 10,000 Rep.
Access moderator tools
Badges
9 26
Newest
 Enlightened
Impact
~129k people reached

Apr
7
comment show that if $\displaystyle\lim_{n \to \infty} f(n+x)=0$ then $\displaystyle\lim_{x \to \infty}f(x)=0$
Welcome to Math.SE! Could you please post some of your thoughts to approach the problem and we will be glad to give hints and comments.
Apr
7
revised show that if $\displaystyle\lim_{n \to \infty} f(n+x)=0$ then $\displaystyle\lim_{x \to \infty}f(x)=0$
edited title
Apr
7
answered Manipulating $\sin^2(x)$ to fit a specific shape.
Apr
7
revised Manipulating $\sin^2(x)$ to fit a specific shape.
added 29 characters in body
Apr
7
answered stats - limiting distribution
Apr
3
answered Prove this language is not regular
Apr
3
revised Line integrals - parametric
added 34 characters in body
Apr
3
comment Solving inequalities with absolute values on both sides
@Joseph By the way, formally, the intersection between sets is never zero, but rather is said to be empty.
Apr
3
comment Solving inequalities with absolute values on both sides
@Joseph please see the edit
Apr
3
revised Solving inequalities with absolute values on both sides
added 999 characters in body
Apr
3
comment Solving inequalities with absolute values on both sides
@Joseph yes, they go by intersection. The second inequality splits, e.g. into $(2x-1) + |1-x| \ge 3$ and $-(2x-1) + |1-x| \ge 3$.
Apr
3
answered Solving inequalities with absolute values on both sides
Apr
3
comment Evaluate the geometric series or state that it diverges.
@Mahina You compute the terms by "plugging in" the values $k=1,2,3$ into the formula in the sum: $4\left(\frac{-1}{5}\right)^{4\cdot 1}, 4\left(\frac{-1}{5}\right)^{4\cdot 2}, 4\left(\frac{-1}{5}\right)^{4\cdot 3}$. Simplify these, and then you get first term to be $a$ and ratio to be $r$. Check that ratio of 2nd/1st and 3rd/2nd terms is the same.
Apr
3
comment Evaluate the geometric series or state that it diverges.
@Mahina Ignore? Why? Write out the first three terms, what are they?
Apr
3
answered Evaluate the geometric series or state that it diverges.
Apr
3
revised Evaluate the geometric series or state that it diverges.
added 29 characters in body; edited tags
Apr
3
revised When taking subsequent derivatives, why are units squared?
added 31 characters in body
Apr
3
answered Does the series diverge or converge?
Apr
3
comment Have some trouble with limits
Do you know about Taylor series? That would help a lot with (3) and (4). Factor the denominator of (2) at $a^3-b^3$ with $a = \sqrt[3]{x}, b= 1$.
Apr
3
revised Have some trouble with limits
editing