1,308 reputation
622
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location Montreal
age
visits member for 3 years, 7 months
seen Apr 13 at 16:30

Computer scientist student who is trying to study math and trying avoid asking stupid questions on this website.


Jun
19
revised Is it possible to have $\mathbb E S_n \to \infty$ but $\inf S_n = -\infty$ a.s.?
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Jun
19
comment Is it possible to have $\mathbb E S_n \to \infty$ but $\inf S_n = -\infty$ a.s.?
@ByronSchmuland Yeah, you're right about case 1. It should be $S_n = 0$ for all $n$.
Jun
19
asked Is it possible to have $\mathbb E S_n \to \infty$ but $\inf S_n = -\infty$ a.s.?
Jun
18
accepted Sum of positive i.i.d. random variables.
Jun
18
asked Sum of positive i.i.d. random variables.
Jun
17
comment How many ways can $5$ rings be placed on $4$ fingers?
Shouldn't this goes to infinity?
Jun
16
comment combinatorics - Distribution of Distinct Balls into Distinct Boxes
By nPk do you mean $\binom n k$?
Jun
16
comment Convergence to exponential function.
I see my mistake!
Jun
16
accepted Convergence to exponential function.
Jun
14
revised $X,Y$ i.i.d., $X$ and $(X+Y)/\sqrt{2}$ have the same dist., then show that $X$ has a normal distribution
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Jun
14
answered $X,Y$ i.i.d., $X$ and $(X+Y)/\sqrt{2}$ have the same dist., then show that $X$ has a normal distribution
Jun
13
revised Convergence to exponential function.
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Jun
13
asked Convergence to exponential function.
Jun
3
accepted Scheffe’s Theorem
Jun
3
comment Scheffe’s Theorem
@ChrisJanjigian I see, it is $1 \le n \le \infty$. Thanks!
Jun
3
comment Scheffe’s Theorem
@ChrisJanjigian How do we get $\int f_\infty = 1$? Dominated convergence theorem?
Jun
3
asked Scheffe’s Theorem
May
31
comment Difference between $P(Y \ge y)$ and $P(Y > y)$.
Thanks! Somehow I believed the sum should starts from $0$ without much thinking.
May
30
accepted Difference between $P(Y \ge y)$ and $P(Y > y)$.
May
30
comment Difference between $P(Y \ge y)$ and $P(Y > y)$.
As for the sum, I was thinking if $>$ and $\ge$ versions of Lemma 2.2.8 is equivalent. Then we should have $\mathbb E(Y) = \int_0^\infty P (Y \ge y) \, \mathrm dy = \sum_{y \ge 0} P(Y \ge y)$, for $Y$ takes only integer values which seems to be wrong.