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seen Sep 2 at 14:00

Sep
28
comment How do you solve this systems of equations?
if you look below, percusse already solved it out, though I haven't check to see if it is correct. This is in the form Ax = b and you have to solve for x = A^-1 b. Can't recall if R or matlab would handle having variables in A or not.
Sep
28
comment How do you solve this systems of equations?
Right, sorry if I was being a little skeptical but I don't want to give it all away! Otherwise you don't learn. Plus it took me so long to figure out how to code that I got lazy :)
Sep
27
awarded  Teacher
Sep
27
answered How do you solve this systems of equations?
Sep
25
comment Superposition question given two diffeq's
oh, so is it simply just p = 3 and q = 0 if y1(t) solves y′[t]+9.7y[t]=e−0.4tcos[t]?
Sep
23
comment Superposition question given two diffeq's
Oh okay but isn't p = 0, q = 1? The 3 in the y3[t] equation is really throwing me off. I can find the solutions to y1[t] and y2[t]. So if I plug in those solutions into the y3[t] and y3'[t] can't I solve for p and t?
Sep
23
comment Superposition question given two diffeq's
I fixed the equation. This is all I was given on the superposition principle: The superposition principle says: If y1[t] solves y'[t]+r y[t]=f[t] with y[0]=p and if y2[t] solves y'[t]+r y[t]=g[t] with y[0]=q then y3[t]=y1[t]+y2[t] solves y'[t]+r y[t]=f[t]+g[t] with y[0]=p+q. I dont understand how you get py1'(t) + qy2'(t) in the equation.
Sep
23
awarded  Editor
Sep
23
revised Superposition question given two diffeq's
fixed the question
Sep
23
asked Superposition question given two diffeq's