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Oct
10
revised Implications from Characteristic Equation from Second Order Diffeq
added 226 characters in body
Oct
10
asked Implications from Characteristic Equation from Second Order Diffeq
Sep
28
comment How do you solve this systems of equations?
if you look below, percusse already solved it out, though I haven't check to see if it is correct. This is in the form Ax = b and you have to solve for x = A^-1 b. Can't recall if R or matlab would handle having variables in A or not.
Sep
28
comment How do you solve this systems of equations?
Right, sorry if I was being a little skeptical but I don't want to give it all away! Otherwise you don't learn. Plus it took me so long to figure out how to code that I got lazy :)
Sep
27
awarded  Teacher
Sep
27
answered How do you solve this systems of equations?
Sep
25
comment Superposition question given two diffeq's
oh, so is it simply just p = 3 and q = 0 if y1(t) solves y′[t]+9.7y[t]=e−0.4tcos[t]?
Sep
23
comment Superposition question given two diffeq's
Oh okay but isn't p = 0, q = 1? The 3 in the y3[t] equation is really throwing me off. I can find the solutions to y1[t] and y2[t]. So if I plug in those solutions into the y3[t] and y3'[t] can't I solve for p and t?
Sep
23
comment Superposition question given two diffeq's
I fixed the equation. This is all I was given on the superposition principle: The superposition principle says: If y1[t] solves y'[t]+r y[t]=f[t] with y[0]=p and if y2[t] solves y'[t]+r y[t]=g[t] with y[0]=q then y3[t]=y1[t]+y2[t] solves y'[t]+r y[t]=f[t]+g[t] with y[0]=p+q. I dont understand how you get py1'(t) + qy2'(t) in the equation.
Sep
23
awarded  Editor
Sep
23
revised Superposition question given two diffeq's
fixed the question
Sep
23
asked Superposition question given two diffeq's