Reputation
28,838
Next tag badge:
91/100 score
25/20 answers
Badges
3 20 73
Newest
 Nice Answer
Impact
~130k people reached

5h
revised find all continuous functions $f:\mathbb{R}^n \rightarrow \mathbb{R}$ satisfying $f(x+y)+f(x-y)=2f(x)+2f(y)$ for all $x,y \in \mathbb{R}^n$
added 1693 characters in body
1d
answered find all continuous functions $f:\mathbb{R}^n \rightarrow \mathbb{R}$ satisfying $f(x+y)+f(x-y)=2f(x)+2f(y)$ for all $x,y \in \mathbb{R}^n$
1d
comment Result of a $2D$ random walk with position dependent probabilities
@Michael [I deleted my last comment which has become obsolete since your last edit]. You claim that "The event of eventually hitting the $x$-axis is independent of the event of eventually hitting the $y$-axis". Could you elaborate on that ?
2d
comment Prove that $f=x^6+ax+5$ is reducible over $\mathbb{Z_7},\forall a\in\mathbb{Z_7}$
@Lucas $f$ is reducible or it is not. You cannot say, "f is reducible for this value and f is not reducible for this other value."
2d
comment Prove that $f=x^6+ax+5$ is reducible over $\mathbb{Z_7},\forall a\in\mathbb{Z_7}$
when $a\neq 0$, $a^{-1}$ is a root of $f$, so $x-a^{-1}$ is a linear factor of $f$.
2d
revised Number theory, prime numbers
added 456 characters in body
2d
answered Number theory, prime numbers
2d
answered how to show that$ n<{2n \choose n}$ in sets
May
25
accepted Interpolation with nonvanishing constraint
May
25
asked Interpolation with nonvanishing constraint
May
25
answered Three planes in general position, one point in each, construct sections
May
24
comment Show that $|\operatorname{Aut}(\mathbb{Q}(\sqrt[10]2))|=2$
@JuniorSoares Your presumption is correct, and Gregory Grant's comment explains why. If $\theta$ is any root of $X^{10}-2$ in $\mathbb K$, then $\alpha=\frac{\theta}{\sqrt[10]{2}}$ is also in $\mathbb K$, and is a tenth root of unity.
May
24
answered Show that $|\operatorname{Aut}(\mathbb{Q}(\sqrt[10]2))|=2$
May
20
comment Show that $a_n=\frac{1}{2}+\frac{1}{3}+…+\frac{1}{n}$ would not contain a natural number for all n
This is definitely a duplicate of another MSE question, unfortunately I can't remember the link right now
May
18
revised Matrices over $\mathbb{Q}[x,y,z]$ which are not equivalent
deleted 150 characters in body
May
17
answered Matrices over $\mathbb{Q}[x,y,z]$ which are not equivalent
May
15
comment Three planes in general position, one point in each, construct sections
@RicardoCruz No you can't use a compass (that would make an interesting other problem though).
May
11
comment Three planes in general position, one point in each, construct sections
@RoryDaulton By the way, if you don't like 3D space the original question is clearly equivalent to a similar question in the 2D plane (consider the set $\cal S$ in a plane instead of in the 3D space).
May
11
comment Three planes in general position, one point in each, construct sections
@RoryDaulton It should be clear that we are making a 2D drawing to represent a 3D reality, with the usual conventions. Also, the last paragraph in the OP clarifies this.
May
11
revised Three planes in general position, one point in each, construct sections
added 2 characters in body