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Dec
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comment Localization $U^{-1} N$ where $U = R^{\times}$ is the set of nonzero elements of an integral domain.
As $R$ is an integral domain, $R$ does not have zero divisors, hence $ab = 0$ with $a \ne 0$ implies $b = 0$. Now use this for $u'(un'' - u''n) = 0$. And: I did not invert your notation, I corrected your correction: You corrected $(u',n) \sim (u,n)$ to $(u',n) \sim (u,n')$, but the correct thing is $(u',n') \sim (u,n)$. (Think of $(u,n)$ as $\frac un$).
Dec
22
revised Localization $U^{-1} N$ where $U = R^{\times}$ is the set of nonzero elements of an integral domain.
added 10 characters in body
Dec
22
comment Localization $U^{-1} N$ where $U = R^{\times}$ is the set of nonzero elements of an integral domain.
Commutativity ... $R$ is an integral domain ...
Dec
22
answered Localization $U^{-1} N$ where $U = R^{\times}$ is the set of nonzero elements of an integral domain.
Dec
21
answered Isomorphic quotient groups $\frac{G}{H} \cong \frac{G}{K}$ imply $H \cong K$?
Dec
21
answered Prove an inequality involving a norm
Dec
21
answered Weird partitions of the real line
Dec
21
answered Definition of the category of group representations
Dec
21
answered Prove convergence to zero of $f(t + x) - f(x)$ in the $L^p$-norm
Dec
19
awarded  sequences-and-series
Dec
18
answered construction of line segment of a length $A^2$
Dec
18
answered Distance between $(-3, 0, 1)$ and the line $(2t, -t, -4t)$
Dec
18
answered Infinite sums of reciprocal power: $\sum\frac1{n^{2}}$ over odd integers
Dec
17
comment Prove/Disprove: if REFF of $A,B \in M_{nxn}(\mathbb R)$ is $A_R , B_R$, then REFF of $A+B$ is $(A_R + B_R)$
REFF?${}{}{}{}$
Dec
17
answered If $n$ is a product of primes, what is the number of divisors?
Dec
17
answered How many zero divisors are in a finite ring?