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1d
reviewed Approve Determine the roots of equation if possible
Jun
26
comment Hilbert space and uncountable cardinal
You should ask this as a seperate question, but the answer is yes. Consider $$ \mathbf K^{(\kappa)} := \left\{ x \colon \kappa \to \mathbf K \biggm| x^{-1}[\mathbf K \setminus \{0\}] \text{ is finite} \right\} $$ this space has $e^i$, $i \in \kappa$ (defined as above) as basis.
Jun
26
answered Hilbert space and uncountable cardinal
Jun
26
answered Method for finding intersection between two basis
Jun
25
awarded  Good Answer
Jun
24
answered Why does the matrix product of jacobian of coordinate transformation and jacobin of reverse coordinate transformation equals the identity matrix
Jun
22
comment Graph vertex set with a certain property
@Arthur Doesn't $V_1$ allready have the stated property? Let $v \in V(G)$ be connected to all vertices in $V_1$. Then $v$ is connected to all vertices in $V_0$ (as $V_0 \subseteq V_1$), hence $v \in V_1$.
Jun
22
revised About the exact form of a gaussian kernel
fixed LaTeX
Jun
22
answered Prove $\operatorname{ann}_r(S)$ is an ideal.
Jun
18
revised To find norm of $T, T(x) = x+M$
added 267 characters in body
Jun
18
answered $T$ induces a natural linear map $L : N/K\to M$
Jun
18
comment What is the most intuitive explanation for euler's identity?
$-1$ is one unit to the left ($\pi$ radians from the right, i.e. postive direction) of $0$?
Jun
18
answered To find norm of $T, T(x) = x+M$
Jun
18
revised Finding the Inverse of this function
added 62 characters in body
Jun
12
answered Markov chain and conditional entropy
Jun
5
comment To show $B^2$ is diagonalizable
You can also use that (multiply $AB = BA^{-1}$ from the left with $A^{-1}$ and from the right with $A$) $BA = A^{-1}B$ and then directly $$ AB^2 = BA^{-1}B = B^2A $$
Jun
5
answered To show $B^2$ is diagonalizable
Jun
5
answered Adjoint of $T_A = Ax$
Jun
4
answered Surjectivity and injectivity
Jun
4
answered Transference of properties from marginals to joint density functions