# user667648

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bio website location age member for 2 years, 11 months seen Jul 9 at 7:13 profile views 98

 Jul7 comment Calculate $\sum_{k=1}^n \frac 1 {(k+1)(k+2)}$ I like how the top two answers, at least at the moment, are virtually identical... Jul6 suggested suggested edit on Limits of $s(x)$ and $H(x)$ Jul6 comment Mathematical Induction Problem with Fraction @Kekker: So since $16 \neq 17$ does this equation hold for $n=2$? And what can you say about all $n$? Jul2 awarded Curious Jun30 awarded Popular Question Jun30 comment Prove that $\lim\limits_{x \to 0} \sinh(x)/x =1$. I don't know if editing this would change the intent of this question... but, $\lim_{x \to 0} \frac{\sinh x}{x} \neq 0$ Jun30 comment Prove that $\lim\limits_{x \to 0} \sinh(x)/x =1$. \sin hx should be \sinh x... :) Jun29 comment Draw a function $g$ such that $g$ is defined on the interval $[-9,9]$ Are you sure the question said: $lim_{x\rightarrow 5} g(x)$ does not exist? Are you sure it isn't supposed to be $-5$? Jun29 revised Algebra and quadratic equations Added latex. Jun29 comment Algebra and quadratic equations What do you think the answer is? Jun29 suggested suggested edit on Algebra and quadratic equations Jun28 comment Find $G'\left( x\right)$. You don't want G^', you just need G'... That will stop the latex error. Jun28 comment How to interpret integration of a discontinous function I believe it has to do with (informally speaking): Rationals are countably infinite, irrationals are uncountably infinite... Hence, the point discontinuities of the rationals are insignificant in the end. Which is why the integral is zero. Someone correct me if I'm wrong. Jun28 comment When are there no critical points? @Gahawar: Wouldn't that function have a critical point everywhere? Since there exists no derivative? Jun28 revised Why is the function integrable? added 2 characters in body Jun28 revised Why is the function integrable? added 6 characters in body Jun28 answered Why is the function integrable? Jun27 comment What do I not understand about one-to-one functions? @JBKing: Sorry I meant -1... Typed it too quickly. Jun27 accepted What do I not understand about one-to-one functions? Jun27 comment What do I not understand about one-to-one functions? @JBKing: And thus, two-to-two, would mean that given a point, for any other arbitrary point it must not produce the same output! And in the case of x^2 it does, give x = 1, y = 1, let x_2 = -1, y = 1 thus it is not injective!