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location Berkeley, CA
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visits member for 3 years, 3 months
seen 4 hours ago

My name is a lie, it's actually Jiggly's bair. Not pound lol.


Sep
1
comment Help with determining irrationality of a number?
@Winther: Thank you so much for your help! I will accept!
Sep
1
comment Help with determining irrationality of a number?
@Winther: Oh! Oh! I think it get it! So is it since $(-1)^a$ where $a$ is an integer implies that the solution is either $-1$ or $1$, but since we can see that $(1/3 + i\frac{2\sqrt{2}}{3})^b$ is not an integer then this implies that $\alpha$ is not an integer? Is my thinking correct?
Sep
1
comment Help with determining irrationality of a number?
@alex.jordan: Honestly, I thought it had to be real...
Sep
1
asked Help with determining irrationality of a number?
Sep
1
comment May I have a hint for this gcd problem?
Yep, that's what I meant. Thanks!
Sep
1
accepted May I have a hint for this gcd problem?
Sep
1
comment May I have a hint for this gcd problem?
Am I correct in my interpretation?
Sep
1
comment May I have a hint for this gcd problem?
Ahh, I actually did try something like this, but forgot you could multiply $(2^b - 1)$ by $2^{a-b}$ too... This makes things clearer. So it's kind of like the identity property $\gcd(a,b) = \gcd(a,b)$, mixed with the fact that $\gcd(a,b)$ is (I believe) an isomorphism to $\gcd(2^a - 1, 2^b-1) = 2^{(a,b)} - 1$, $\therefore \gcd(2^a - 1, 2^b-1) = 2^{(a,b)} - 1$?
Sep
1
comment May I have a hint for this gcd problem?
@ThomasAndrews: The set of notes I'm looking at here (cs.berkeley.edu/~oholtz/H90/integers.pdf) puts "Congruences" after this, so I'm trying to avoid modular arithmetic. (Unless I am mistaken and they are not the same thing, which could very well be the case). But thank you for the suggestion.
Sep
1
asked May I have a hint for this gcd problem?
Aug
30
accepted Question about proof of Cauchy-Schwarz inequality.
Aug
30
comment Question about proof of Cauchy-Schwarz inequality.
I see, the usage of the unit vector is kind of like justification for normalization, ok, ok. Sorry, I didn't stare at it hard enough I guess.
Aug
30
comment Question about proof of Cauchy-Schwarz inequality.
O wait, I think I understand...
Aug
30
comment Question about proof of Cauchy-Schwarz inequality.
When I read this proof, it makes sense. But, the original proof doesn't use the properties of linearity to prove the inequality. On one hand, you have confirmed beyond doubt that the proof has confirmed beyond doubt that it must work in the interval $(0,1)$, but by doing something (that feels) different altogether. Is there way to justify the current outline of proof? Sorry if what I am saying doesn't make sense.
Aug
30
asked Question about proof of Cauchy-Schwarz inequality.
Jul
7
comment Calculate $\sum_{k=1}^n \frac 1 {(k+1)(k+2)}$
I like how the top two answers, at least at the moment, are virtually identical...
Jul
6
suggested suggested edit on Limits of $s(x)$ and $H(x)$
Jul
6
comment Mathematical Induction Problem with Fraction
@Kekker: So since $16 \neq 17$ does this equation hold for $n=2$? And what can you say about all $n$?
Jul
2
awarded  Curious
Jun
30
awarded  Popular Question