Pound

less info
reputation
215
bio website location Berkeley, CA age member for 3 years, 3 months seen 4 hours ago profile views 126

My name is a lie, it's actually Jiggly's bair. Not pound lol.

189 Actions

 Sep1 comment Help with determining irrationality of a number? @Winther: Thank you so much for your help! I will accept! Sep1 comment Help with determining irrationality of a number? @Winther: Oh! Oh! I think it get it! So is it since $(-1)^a$ where $a$ is an integer implies that the solution is either $-1$ or $1$, but since we can see that $(1/3 + i\frac{2\sqrt{2}}{3})^b$ is not an integer then this implies that $\alpha$ is not an integer? Is my thinking correct? Sep1 comment Help with determining irrationality of a number? @alex.jordan: Honestly, I thought it had to be real... Sep1 asked Help with determining irrationality of a number? Sep1 comment May I have a hint for this gcd problem? Yep, that's what I meant. Thanks! Sep1 accepted May I have a hint for this gcd problem? Sep1 comment May I have a hint for this gcd problem? Am I correct in my interpretation? Sep1 comment May I have a hint for this gcd problem? Ahh, I actually did try something like this, but forgot you could multiply $(2^b - 1)$ by $2^{a-b}$ too... This makes things clearer. So it's kind of like the identity property $\gcd(a,b) = \gcd(a,b)$, mixed with the fact that $\gcd(a,b)$ is (I believe) an isomorphism to $\gcd(2^a - 1, 2^b-1) = 2^{(a,b)} - 1$, $\therefore \gcd(2^a - 1, 2^b-1) = 2^{(a,b)} - 1$? Sep1 comment May I have a hint for this gcd problem? @ThomasAndrews: The set of notes I'm looking at here (cs.berkeley.edu/~oholtz/H90/integers.pdf) puts "Congruences" after this, so I'm trying to avoid modular arithmetic. (Unless I am mistaken and they are not the same thing, which could very well be the case). But thank you for the suggestion. Sep1 asked May I have a hint for this gcd problem? Aug30 accepted Question about proof of Cauchy-Schwarz inequality. Aug30 comment Question about proof of Cauchy-Schwarz inequality. I see, the usage of the unit vector is kind of like justification for normalization, ok, ok. Sorry, I didn't stare at it hard enough I guess. Aug30 comment Question about proof of Cauchy-Schwarz inequality. O wait, I think I understand... Aug30 comment Question about proof of Cauchy-Schwarz inequality. When I read this proof, it makes sense. But, the original proof doesn't use the properties of linearity to prove the inequality. On one hand, you have confirmed beyond doubt that the proof has confirmed beyond doubt that it must work in the interval $(0,1)$, but by doing something (that feels) different altogether. Is there way to justify the current outline of proof? Sorry if what I am saying doesn't make sense. Aug30 asked Question about proof of Cauchy-Schwarz inequality. Jul7 comment Calculate $\sum_{k=1}^n \frac 1 {(k+1)(k+2)}$ I like how the top two answers, at least at the moment, are virtually identical... Jul6 suggested suggested edit on Limits of $s(x)$ and $H(x)$ Jul6 comment Mathematical Induction Problem with Fraction @Kekker: So since $16 \neq 17$ does this equation hold for $n=2$? And what can you say about all $n$? Jul2 awarded Curious Jun30 awarded Popular Question