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 May14 suggested rejected edit on complex nos in ellipse. May12 comment Quadratic solutions puzzle (-1/2, -1/2) is a solution, but it is also said in the constraints that $a \neq b$. May11 comment Confused about the prime elements of a ring. @BillDubuque: Ok, thanks! It is just hard to wrap my head around. A lot of things in abstract algebra are requiring some serious rewiring of my brain. sigh May11 comment Confused about the prime elements of a ring. @BillDubuque: Ok, so then we can construct any numerator as a unique combination of primes (well known property of primes) and choose a specific bottom element as a particular unit so this would imply that R is a UFD then? May11 comment Confused about the prime elements of a ring. @BillDubuque: When you say $2$ is a unit, are you referring to the $p \times 2^{-1}$ is unnecessary just as $-1$ is unnecessary in prime factorization? May11 asked Confused about the prime elements of a ring. May10 awarded Yearling May10 accepted Need help determining what this center is isomorphic to May10 comment Need help determining what this center is isomorphic to Oh, whoops my bad, but $Z$ should have order $2$. That was me slipping up there, I didn't mean to write that, just mixed things around sorry about that. Thanks! (Modified original comment.) May10 comment Need help determining what this center is isomorphic to Ok, so I think the problem is I didn't know about p-group. In this case the argument should go: Since it is non-trivial, we know that the order is $2$, $4$ or $8$, but G is not abelian so the order cannot be $8$ and $2$ is guaranteed cyclic hence $Z$ has order $2$ and $|G/Z| = 4$ May10 asked Need help determining what this center is isomorphic to May8 accepted Help show the following isomorphism cannot exist. May8 comment Help show the following isomorphism cannot exist. Ok, so I think I get it, I made a small typo in my question, but was able to follow through and get $v^2 - v + 1 = 0$. But still, $x^2 - x + 1 \not\in \langle g(x) \rangle$. Thanks! May8 revised Help show the following isomorphism cannot exist. edited body May8 comment Help show the following isomorphism cannot exist. I still applied simplifications as if it was $\mathbb{Z}_3$ if that is what you are wondering... May8 revised Help show the following isomorphism cannot exist. added 4 characters in body May8 comment Help show the following isomorphism cannot exist. Oops, sorry about that. May8 asked Help show the following isomorphism cannot exist. May5 comment a question about abstract algebra,the order of $\Bbb Z_{5}[x]/ (x^3+x+1)$ Beat me too it too. +1 May4 accepted Finding an ideal such that $\mathbb{Z}[x]/I \cong \mathbb{Z}[i]$.