Sb Sangpi
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 Apr 22 comment Find $g'(3)$ if $g(x)$ sorry 4 another question,i did this another question $\frac{3x+1}{f(x)}$ it doesn't work. Apr 22 comment Find $\frac{dy}{dx}$ when $y=\frac{x^2-1}{x^4-1}$ my bad, thx alot! @anon Apr 22 comment Find $\frac{dy}{dx}$ when $y=\frac{x^2-1}{x^4-1}$ yea. i did it upto this step but, the answer is not right Apr 17 comment Find all values of $x$ between 0 and $2\pi$ for which $\sin x=0.6$ sorry, I just edited question! Apr 17 comment Find all values of $x$ between 0 and $2\pi$ for which $\sin x=0.6$ sorrry I just edited question! Apr 17 comment Find all values of $x$ between 0 and $2\pi$ for which $\sin x=0.6$ so, I must use calculator to solve this question? thx Apr 13 comment Find the gradient of the curve at the stated point? thx, my mistake! Apr 13 comment Find the gradient of the curve at the stated point? i got $y'=28$ and....? thx Apr 13 comment Calculate the value of a and b. @azarel $7=-\frac{18-27b}{9}$ then $7=3b-2+6b$ but I didn't see 7 in this step in ur answer. thx Apr 13 comment Calculate the value of a and b. aww..i see, so sorry, $a+27b=18$ then $a=18-27b$ Apr 13 comment Calculate the value of a and b. how did $a=18-27b$, i got only $18=a+27b$, thx. Apr 13 comment Calculate the value of a and b. yes, i don't know how to do further. thx :) Apr 12 comment Find the gradient of the curve? $\frac{-2x+8}{x^3}$ shouldn't be $\frac{-2x+8}{4x^3}$ or u cancel by $x$? thx alot. Apr 12 comment Find the gradient of the curve? why not derivative is $y=\frac{2}{2x}$ and how did it into $y'=\frac{2x^2-2x(2x-4)}{x^4}$ can u explain? thx Apr 10 comment Find the values of $a$ and $b$ $-2=8a+b$ and $-5=16a-b$ but still can't get $a=-1$ and $b=4$ sorry about that! Apr 10 comment Find the values of $a$ and $b$ then where is $8a+b=-4$ gone?, sorry for my lack of maths. Apr 10 comment Find the values of $a$ and $b$ how did $8a+b=-4$ into $16a-b=-20$? Apr 10 comment Find the values of $a$ and $b$ but still can't solve! can you explain more? thx Apr 7 comment Find the Derivative in step by step? no! I havn't learn yet. Apr 6 comment Differentiate respect to $x$ yea.I'm confuse with du/dx that's why I try to guess one by one to get answer!